Answer:
look at the picture to be more clear.
Hope it helps
F(x) = x²-81
g(x) = (x-9) -1(x+9)
= (x-9) -x-9
g(x) • f(x)
= [x²-81 ] • [ (x-9) -x-9 ]
=[ x²-81 ] • [ (x-x -9-9) ]
= [ x²-81 ] •[0-18]
= [ x²-81] •[ -18]
= -18•x² +-81•-18
= -18x²+1458
The GCF of 10 and 6 is 2. May this will help you.
The answer is three significant figures. The 1 and the 7 are both significant, because they are non-zero quantities.
This is where significant figures gets a little more complicated, because if a zero is used as a placeholder (i.e. 0.00027 cm) then it is insignificant.
But in the case above, the zero isn't being used as a placeholder, and thus, is significant.
Total: 73
dogs: x
cats: 2x+10
2x+10+x=73
3x+10=73
3x=63
x=21
dogs: x
dogs: 21
cats: 2x+10
cats: 52
Check answer:
cats+dogs=73
52+21=73
There's no need for a system of linear equations if you were to solve a real life problem like this. In calculus, they don't give a rat about HOW you get your answer to an easy algebra 1 equation, as long as you used one of the correct methods and got the right answer.
Best of luck my friend. :)