(-2,6) (5,-8)
slope = (y2 - y1) / (x2 - x1)
slope = (-8 - 6) / (5 - (-2) = -14/7 = -2 <==
midpoint = (x1 + x2)/2 , (y1 + y2)/2
m = (-2 + 5)/2 , (6 - 8)/2
m = (3/2, -1) <===
distance = sqrt ((x2 - x1)^2 + (y2 - y1)^2)
d = sqrt ((5 - (-2)^2 + (-8 - 6)^2)
d = sqrt ((5 + 2)^2 + (-14^2))
d = sqrt (7^2 + 14^2)
d = sqrt (49 + 196)
d = sqrt 245
d = 15.65 <==
Answer:
x = 
Step-by-step explanation:
3x+6 = 4x^2
4x^2 -3x -6 = 0
x =
Answer:
Supplement of <1 = 122°
Supplement of <2 = 156°
Step-by-step explanation:
Two pairs of angles are said to be supplementary, if their measures in degrees add up to give us 180°. A supplement of am angle is simply 180° - the measure of that angle.
Given that meadure of angle 1 = 58°, the supplement of angle 1 = 180° - 58° = 122°
Also, if the measure of angle 2 = 24°, the supplement of angle 2 = 180° - 24° = 156°.
Thus:
Supplement of <1 = 122°
Supplement of <2 = 156°
Is there not more to this problem? maybe thats the final answers
