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Anna007 [38]
3 years ago
15

The average american eats about 30 pounds of cheese per year. This is 3/5 the amount eaten my the average French person. How man

y pounds of cheese does a French pers person eat in one year?
Mathematics
1 answer:
iragen [17]3 years ago
7 0
What's 30-3/5???????
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ANSWER PLZ QUICK AND FAST
kotykmax [81]

Hi!

The answer is C. It is a numerical expression because it contains only numbers and operation symbols.

4 0
3 years ago
a rectangular lawn has an area of a^3 - 125. use the difference of cubes to find out the dimensions of the rectangle.
ANEK [815]

The area of a rectangle is the product of its dimensions

The dimensions of the rectangle are: \mathbf{Length = a -5} and \mathbf{Width = a^2 + 5a + 25}

The area is given as:

\mathbf{Area = a^3 - 125}

Express 125 as 5^3

\mathbf{Area = a^3 - 5^3}

Apply difference of cubes

\mathbf{Area = (a - 5)(a^2 + 5a + 5^2)}

\mathbf{Area = (a - 5)(a^2 + 5a + 25)}

The area of a rectangle is:

\mathbf{Area = Length \times Width}

So, by comparison:

\mathbf{Length = a -5}

\mathbf{Width = a^2 + 5a + 25}

Read more about areas at:

brainly.com/question/3518080

6 0
2 years ago
What is the solution to the problem 2y+3=4y+2
yulyashka [42]

Answer:

y = 1/2

Step-by-step explanation:

<u>Step 1:  Solve for y</u>

2y + 3 = 4y + 2

2y + 3 - 2 - 2y = 4y + 2 - 2 - 2y

1 / 2 = 2y / 2

1/2 = y

Answer:  y = 1/2

8 0
2 years ago
Read 2 more answers
Theo drove 236 miles in 4 hours. Lex drove 195 miles in 3 hours. At those rates, could either man drive 116 miles in 2 hours? Sh
motikmotik

Answer:

No.

Step-by-step explanation:

236÷4=59

     &

195÷3=65

<em>To check if either of them drove 116 miles in 2 hours, I would multiply the sum of the division problems by 2(for 2 hours).</em>

59 x 2 = 118

      &

65 x 2 = 130

None of them equals 116, meaning neither of them drove 116 miles in 2 hours.

<u><em>Hope I helped you! Have a great day! :)</em></u>

6 0
3 years ago
Write the linear equation
valina [46]

Answer:

y=-3/2x+4

slope=-3/2

y-int= 4

6 0
3 years ago
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