Answer:
a) f g(x) = x³ - 5 x² + x -5
b) g(f(x) = x³ - 5 x² + x -5
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that f(x) = x² + 1 and g(x) = x-5
a)
f(g(x)) = f(x-5) = (x-5)²+1 = x² - 10x +25 +1 = x² - 10 x +26
<u><em>Step(ii):-</em></u>
a) f g(x) = f(x) g(x) = (x² + 1 )(x-5) = x³ - 5 x² + x -5
b) g(f(x) = g(x) f(x) = (x-5) (x²+1) = x³ - 5 x² + x -5
Well 6×12=72. I don't know what the original tank size was but subtract the original from this one to get your answer.
Answer:
<h2>A. 1</h2>
Step-by-step explanation:
Use:
|a| = a for a ≥ 0 or |a| = -a for a < 0
PEMDAS:
P Parentheses first
E Exponents
MD Multiplication and Division (left-to-right)
AS Addition and Subtraction (left-to-right)
========================================
|8 - 7| · 4 + 3(-1)
= |1| · 4 - 3
= 1 · 4 - 3
= 4 - 3
= 1
Threeeeeeeeeeeeeeeeeeeeeeeeee
