The formula for average velocity between two times t1 and t2 of the position function f(x) is (f(t2)-f(t1)) / (t2-t1)
Plugging the values in for the first time period we get (f(2.5)-f(2)) / (2.5-2)
=> (f(2.5)-f(2)) / 0.5
f(2) will be the same for all 4 time periods and is
48(2)-16(2)^2 = 32
Now we plugin the other values
f(2.5) = 48(2.5)-16(2.5)^2 = 20
f(2.1) = 48(2.1)-16(2.1)^2 = 30.25
etc.
f(2.05) = 31.16
f(2.01) = 31.8384
Now plug these values into the formula
(20-32)/0.5 = -24
(30.25-32)/0.1 = -17.5
etc.
= -16.8
= -16.16
Final answer:
2.5s => -24 ft/s
2.1s => -17.5 ft/s
2.05 => -16.8 ft/s
2.01 => -16.16 ft/s
Hope I helped :)
Answer:
3) 2.7
Step-by-step explanation:
The distance between two points 
and 
can be determined by:
Since the points are X(1, 2) and Y(6, 7). The distance between the two points is
the x value for the point located 1/3 the distance from X to Y,
The x value = 
Answer:
x=13
Step-by-step explanation:
15x-15
15*13=195
195-15=180
Answer:
.016 kilometers
Step-by-step explanation:
A kilometer is 1000 meters. Divide the length of the markers by 1000 (16/1000) and you get the answer of .016 kilometers.
