Answer:
perimeter of the shaded region = 88 +44+28 =160 cm
Step-by-step explanation:
perimeter of shaded region = length AO + arc OB + arc AB
length AO = radius of bigger circle
radius of bigger circle = OX + OB = 2×radius of smaller circle = 2×14 cm = 28 cm
therefore AO = 28 cm
length of arc oB= half of circumference of smaller circle =
×14 = 44 cm
length of arc ab = half of circumference of bigger circle =
×28 =
×28= 88
therefore perimeter of the shaded region = 88 +44+28 =160 cm
area of the shaded region = half of area of bigger circle - half of area of smaller circle
=
=
solving we gen area of shaded region = 924
D) Daniel’s Brick
This is because it has the most bricks close to 2.5 inches.
Answer:
125
Step-by-step explanation:
2375/19
Answer:
SAS Similarity
Step-by-step explanation:
ΔOPQ similar to ΔRST
∠Q = ∠T
OQ : RT = 28 : 84 = 1 : 3
QP : TS = 16 : 48 = 1 : 3
The measures of two sides of ΔOPQ are proportional to the measure of two side of ΔRST and their included angles are congruent. The triangles are similar by SAS Similarity.