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Kipish [7]
3 years ago
13

Find the anwser to y=2x -4. & 4x+y=2

Mathematics
1 answer:
Aleks04 [339]3 years ago
6 0
Y= 2x-4
4x+Y=2

4x+2x-4=2
6x-4=2
+4=+4
6x=6
6/6X = 6/6 X=1
Y=2X-4
2(1)-4
Y=-2
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The diameter of this
o-na [289]

Answer:

The number of coins to make 6440 mm diameter is 230

Step-by-step explanation:

The diameter of the coin is 28mm

Number of coins to have 6440 mm will be

6440/28

= 230

8 0
3 years ago
Last year, Manuel deposited $7000 into an account that paid 11% interest per year and $1000 into an account that paid 5% interes
Westkost [7]

Answer:

The total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.

Step-by-step explanation:

Given that last year, Manuel deposited $ 7000 into an account that paid 11% interest per year and $ 1000 into an account that paid 5% interest per year, and no withdrawals were made from the accounts, to determine what was the total interest earned at the end of year and what was the percent interest for the total deposited, the following calculations must be performed:

7000 x 0.11 + 1000 x 0.05 = X

770 + 50 = X

820 = X

8000 = 100

820 = X

820 x 100/8000 = X

82,000 / 8,000 = X

10.25 = X

Therefore, the total interest earned at the end of the year was $ 820, and the interest generated by the total deposited was 10.25%.

5 0
3 years ago
Please help me outtt ~ I’ll give u brain
Hunter-Best [27]
The answer is no because the problem has no solution. Hope this helps
4 0
3 years ago
If cosine theta equals negative square root of three over two and pi over two less than theta less than pi, what are the values
Natalka [10]
<h2>Answer:</h2>

The values of sinθ and tanθ are:

\sin \theta=\dfrac{1}{2}

and

\tan \theta=-\dfrac{1}{\sqrt{3}}=-\dfrac{\sqrt{3}}{3}

<h2>Step-by-step explanation:</h2>

It is given that:

\cos \theta=-\dfrac{\sqrt{3}}{2}

where

\dfrac{\pi}{2}

i.e. the angle θ lie in the second quadrant.

Also, we know that in the second quadrant sine and cosecant function is positive.

whereas cosine,secant, tangent and cotangent functions are negative.

Now, we know that:

\cos (\dfrac{5\pi}{6})=-\dfrac{\sqrt{3}}{2}

i.e. here

\theta=\dfrac{5\pi}{6}

Hence, we have:

\sin (\theta)=\sin (\dfrac{5\pi}{6})\\\\i.e.\\\\\sin \theta=\dfrac{1}{2}

Also,

\tan \theta=\dfrac{\sin \theta}{\cos \theta}\\\\i.e.\\\\\tan \theta=\dfrac{\dfrac{1}{2}}{\dfrac{-\sqrt{3}}{2}}\\\\i.e.\\\\\tan \theta=\dfrac{1}{-\sqrt{3}}\\\\i.e.\\\\\tan \theta=-\dfrac{1}{\sqrt{3}}

Now, on rationalizing we have:

\tan \theta=-\dfrac{\sqrt{3}}{3}

7 0
4 years ago
Read 2 more answers
What is the scale factor? ( the answer must be a fraction).
MrRissso [65]
Since these are similar triangles you can use any two corresponding sides to figure out the scale factor.

Use the bottom side. Going from the first triangle to the second the scale factor is:
15/9 = 5/3
8 0
3 years ago
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