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natka813 [3]
3 years ago
10

How would I graph and solve this inequality?? Help please! Press question to view image.

Mathematics
2 answers:
Veronika [31]3 years ago
7 0
Well, x has to be anything from 5 or below, as it has to be subtracted by three and the answer has to be less than 4. so, x=y<5 (first one)

negative 3 times a number = less than negative 12. so, the higher the number, but negative, is less than. (example:-52<-3) so, |x| is x=4>y
sorry if unclear...
yan [13]3 years ago
6 0
Check the picture below.

\bf |x|-3\le 4\implies |x|\le 7\implies \boxed{-7\le x\le 7}&#10;\\\\\\&#10;-3|x|\ \textless \ -12\implies |x|\ \textgreater \ \cfrac{-12}{-3}\implies |x|\ \textgreater \ 4\implies \boxed{4\ \textless \ x\ \textless \ -4}

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3 years ago
Read 2 more answers
suppose that the lifetime of a transistor is a gamma random variable x with mean of 24 weeks and standard deviation of 12 weeks.
emmainna [20.7K]

The probability that the transistor will last between 12 and 24 weeks is 0.424

X= lifetime of the transistor in weeks E(X)= 24 weeks

O,= 12 weeks

The anticipated value, variance, and distribution of the random variable X were all provided to us. Finding the parameters alpha and beta is necessary before we can discover the solutions to the difficulties.

X~gamma(\alpha ,\beta)

E(X)= \alpha \beta                 \beta= 12^{2}/24=6 weeks

V(x)= \alpha \beta ^{2}                \alpha=24/6= 4

Now we can find the solutions:

The excel formula used to create Figure one is as follows:

=gammadist(X, \alpha, \beta, False)

P(12\leq X\leq 24)

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P= 0.424

Therefore, probability that the transistor will last between 12 and 24 weeks is 0.424

To learn more about probability click here:

brainly.com/question/11234923

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