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m_a_m_a [10]
3 years ago
5

FIRST CORRECT ANSWER GETS BRAINLIEST!!!

Mathematics
1 answer:
castortr0y [4]3 years ago
6 0
The total material required to cover both is 29 sq. units.

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Four friends are playing the board game Hidden Treasure. The game begins with 40 coins
liraira [26]

Answer:

I hope this helps 40 divided by 4 is 10 10 per person 10-2=8 8 coins in each players bag and the total amount of coins in bags is 8 times 4 which is 32

8 0
1 year ago
What is the equation of the graphed line written in
Andrew [12]

<u>Given</u>:

Given that the graph of the linear equation.

We need to determine the equation of the graph.

<u>Slope</u>:

The slope of the equation can be determined using the formula,

m=\frac{y_2-y_1}{x_2-x_1}

Let us substitute the coordinates (2,0) and (0,-4) in the above formula, we get;

m=\frac{-4-0}{0-2}

m=\frac{-4}{-2}

m=2

Thus, the slope of the equation is 2.

<u>y - intercept:</u>

The y - intercept of the equation is the value of y when x = 0.

Hence, from the graph, it is obvious that when x = 0, the value of y is -4.

Therefore, the value of the y - intercept is b = -4.

<u>Equation of the line:</u>

The equation of the line can be determined using the formula,

y=mx+b

Substituting the values, we have;

y=2x-4

Subtracting both sides by 2x, we have;

-2x+y=-4

Dividing both sides by -1, we get;

2x-y=4

Thus, the equation of the line is 2x-y=4

Hence, Option B is the correct answer.

3 0
2 years ago
Combine like terms: <br>3a + 4b - 6b + 12 - 4
stepan [7]
The answer is 3a + 2b + 8
6 0
2 years ago
Which percent is equivalent to 2 5/6?
Tems11 [23]

Answer:

283.3%

Step-by-step explanation:

5/6 equals 0.83 repeating and it already has 200% for the whole number 2

3 0
3 years ago
Triangle JKL has vertices J(2,5), K(1,1), and L(5,2). Triangle QNP has vertices Q(-4,4), N(-3,0), and P(-7,1). Is (triangle)JKL
Tems11 [23]

Answer:

Yes they are

Step-by-step explanation:

In the triangle JKL, the sides can be calculated as following:

  • J(2;5); K(1;1)

             => JK = \sqrt{(1-2)^{2} + (1-5)^{2}  } = \sqrt{(-1)^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • J(2;5); L(5;2)

             => JL = \sqrt{(5-2)^{2} + (2-5)^{2}  } = \sqrt{3^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • K(1;1); L(5;2)

             =>  KL = \sqrt{(5-1)^{2} + (2-1)^{2}  } = \sqrt{4^{2}+1^{2}  } = \sqrt{1+16}=\sqrt{17}

In the triangle QNP, the sides can be calculate as following:

  • Q(-4;4); N(-3;0)

             => QN = \sqrt{[-3-(-4)]^{2} + (0-4)^{2}  } = \sqrt{1^{2}+(-4)^{2}  } = \sqrt{1+16}=\sqrt{17}

  • Q (-4;4); P(-7;1)

   => QP = \sqrt{[-7-(-4)]^{2} + (1-4)^{2}  } = \sqrt{(-3)^{2}+(-3)^{2}  } = \sqrt{9+9}=\sqrt{18} = 3\sqrt{2}

  • N(-3;0); P(-7;1)

             =>  NP = \sqrt{[-7-(-3)]^{2} + (1-0)^{2}  } = \sqrt{(-4)^{2}+1^{2}  } = \sqrt{16+1}=\sqrt{17}

It can be seen that QPN and JKL have: JK = QN; JL = QP; KL = NP

=> They are congruent triangles

7 0
3 years ago
Read 2 more answers
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