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4 years ago

FIRST CORRECT ANSWER GETS BRAINLIEST!!!

Mathematics

1 answer:

castortr0y [4]4 years ago

6 0

The total material required to cover both is 29 sq. units.

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NEED HELP ASAP IF NOT I WILL FAIL. I WILL MARK YOU AS MOST BRAINIEST

aivan3 [116]

Y= 58x + 55
They charge 58$ per hour therefore 58 should correlate with x and since when don’t know y (the total amount) its y= and then just add 55

7 0

4 years ago

Pumping stations deliver oil at the rate modeled by the function D, given by d of t equals the quotient of 5 times t and the qua

goblinko [34]

<h2>Hello!</h2>

The answer is: There is a total of 5.797 gallons pumped during the given period.

To solve this equation, we need to integrate the function at the given period (from t=0 to t=4)

The given function is:

$D(t)=\frac{5t}{1+3t}$

So, the integral will be:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dx$

So, integrating we have:

$\int\limits^4_0 {\frac{5t}{1+3t}} \ dt=5\int\limits^4_0 {\frac{t}{1+3t}} \ dx$

Performing a change of variable, we have:

$1+t=u\\du=1+3t=3dt\\x=\frac{u-1}{3}$

Then, substituting, we have:

$\frac{5}{3}*\frac{1}{3}\int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du\\\\\frac{5}{9} \int\limits^4_0 {\frac{u-1}{u}} \ du=\frac{5}{9} \int\limits^4_0 {\frac{u}{u} -\frac{1}{u } \ du$

$\frac{5}{9} \int\limits^4_0 {(\frac{u}{u} -\frac{1}{u } )\ du=\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u } )$

$\frac{5}{9} \int\limits^4_0 {(1 -\frac{1}{u })\ du=\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du$

$\frac{5}{9} \int\limits^4_0 {(1 )\ du- \frac{5}{9} \int\limits^4_0 {(\frac{1}{u })\ du=\frac{5}{9} (u-lnu)/[0,4]$

Reverting the change of variable, we have:

$\frac{5}{9} (u-lnu)/[0,4]=\frac{5}{9}((1+3t)-ln(1+3t))/[0,4]$

Then, evaluating we have:

$\frac{5}{9}((1+3t)-ln(1+3t))[0,4]=(\frac{5}{9}((1+3(4)-ln(1+3(4)))-(\frac{5}{9}((1+3(0)-ln(1+3(0)))=\frac{5}{9}(10.435)-\frac{5}{9}(1)=5.797$

So, there is a total of 5.797 gallons pumped during the given period.

Have a nice day!

4 0

4 years ago

G(–2) = –2(–2)2 + 3(–2) – 5<br> g(–2) = –2(4) – 6 – 5<br> g(–2) =

Xelga [282]

Answer:

G(-2)=-8-6-5=-

Step-by-step explanation:

Issue talk to my fist

3 0

4 years ago

clara wants to run a total of 5 1/2 miles each lap around the track is 0.25 miles. how many laps around the track does clara nee

NemiM [27]

Answer:

22 laps

Step-by-step explanation:

Clara wants to run 5 1/2 miles, and the track is only 0.25 miles long. This is a fairly easy question, you just need to figure out how many times 5 1/2 goes into 0.25, because she wants to run that amount of miles (I could never run that much).

I hope that answers your question so you understand, and I hope you have a great rest of your day! :)

5 0

4 years ago

Describe a linear function for which the least value in the range does not occur at the least value of the domain

Nady [450]

Kf xurzrusiwas ltsylslyalysuaulsjfdjDnrkshRjira

6 0

3 years ago