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miss Akunina [59]

3 years ago

5

SMART PEOPLE, PLEASE HELP ASAP

1 answer:

Sever21 [200]3 years ago

8 0

Answer:do you know the Volume formula

Step-by-step explanation:

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Use the Side-Splitting Theorem to find the value of x.

spin [16.1K]

<h2>The required "option D. 9.6" is correct.</h2>

Step-by-step explanation:

In given figure,

AD = x, DB = 12, BE = 8 and EC = 10

To find, the value of x = ?

Use the Side-Splitting Theorem,

We know that,

$\dfrac{AD}{DB} =\dfrac{BE}{EC}$

⇒ $\dfrac{x}{12} =\dfrac{8}{10}$

⇒ x = $\dfrac{8 \times 12}{10}$

⇒ x = $\dfrac{96}{10}$

⇒ x = 9.6

∴ The value of x = 9.6

Thus, the required "option D. 9.6" is correct.

4 0

3 years ago

Multiply. a^5 . a . a^0 . a^-3

stiks02 [169]

$a^5 \cdot a \cdot a^0 \cdot a^{-3}=a^{5+1-3}\cdot 1 = a^3$

6 0

4 years ago

A quarter weighs about 0.0 pounds. What is the weight written in Scientific notation?

faltersainse [42]

I believe it’s the answer is A

7 0

3 years ago

Identify all of the root(s) of g(x) = (x2 + 3x - 4)(x2 - 4x + 29).

Gennadij [26K]

we have

$g(x)=(x^{2}+3x-4)( x^{2}-4x+29)$

To find the roots of g(x)

Find the roots of the first term and then find the roots of the second term

Step 1

Find the roots of the first term

$(x^{2}+3x-4)=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}+3x)=4$

Complete the square. Remember to balance the equation by adding the same constants to each side

$(x^{2}+3x+1.5^{2})=4+1.5^{2}$

$(x^{2}+3x+1.5^{2})=6.25$

Rewrite as perfect squares

$(x+1.5)^{2}=6.25$

Square root both sides

$(x+1.5)=(+/-)2.5$

$x=-1.5(+/-)2.5$

$x=-1.5+2.5=1$

$x=-1.5-2.5=-4$

so the factored form of the first term is

$(x^{2}+3x-4)=(x-1)(x+4)$

Step 2

Find the roots of the second term

$(x^{2}-4x+29)=0$

Group terms that contain the same variable, and move the constant to the opposite side of the equation

$(x^{2}-4x)=-29$

Complete the square. Remember to balance the equation by adding the same constants to each side

$(x^{2}-4x+4)=-29+4$

$(x^{2}-4x+4)=-25$

Rewrite as perfect squares

$(x-2)^{2}=-25$

Remember that

$i=\sqrt{-1}$

Square root both sides

$(x-2)=(+/-)5i$

$x=2(+/-)5i$

$x=2+5i$

$x=2-5i$

so the factored form of the second term is

$(x^{2}-4x+29)=(x-(2+5i))(x-(2-5i))$

Step 3

Substitute the factored form of the first and second term in g(x)

$g(x)=(x-1)(x+4)(x-(2+5i))(x-(2-5i))$

therefore

the answer is

the roots are

$x1=1\\x2=-4\\x3=(2+5i)\\x4=(2-5i)$

8 0

4 years ago

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Answer the question below:

marissa [1.9K]

$12 5 times 3 is 15 -20% is $12

7 0

3 years ago

Read 2 more answers