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AVprozaik [17]
2 years ago
13

Please help me with this math please please asap please

Mathematics
1 answer:
stiks02 [169]2 years ago
6 0

Answer:

50.24 meters

If you chose 50.24 meters and got it wrong, there is a mistake in the problem.

If the radius was 8, the answer would be c

Step-by-step explanation:

The diameter is 2r, therefore, 8 / 2 = 4.

pi multiplied by 4 squared would be 50.24

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An alarming number of U.S. adults are either overweight or obese. The distinction between overweight and obese is made on the ba
madreJ [45]

Answer:

(A) The probability that a randomly selected adult is either overweight or obese is 0.688.

(B) The probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C) The events "overweight" and "obese" exhaustive.

(D) The events "overweight" and "obese" mutually exclusive.

Step-by-step explanation:

Denote the events as follows:

<em>X</em> = a person is overweight

<em>Y</em> = a person is obese.

The information provided is:

A person is overweight if they have BMI 25 or more but below 30.

A person is obese if they have BMI 30 or more.

P (X) = 0.331

P (Y) = 0.357

(A)

The events of a person being overweight or obese cannot occur together.

Since if a person is overweight they have (25 ≤ BMI < 30) and if they are obese they have BMI ≥ 30.

So, P (X ∩ Y) = 0.

Compute the probability that a randomly selected adult is either overweight or obese as follows:

P(X\cup Y)=P(X)+P(Y)-P(X\cap Y)\\=0.331+0.357-0\\=0.688

Thus, the probability that a randomly selected adult is either overweight or obese is 0.688.

(B)

Commute the probability that a randomly selected adult is neither overweight nor obese as follows:

P(X^{c}\cup Y^{c})=1-P(X\cup Y)\\=1-0.688\\=0.312

Thus, the probability that a randomly selected adult is neither overweight nor obese is 0.312.

(C)

If two events cannot occur together, but they form a sample space when combined are known as exhaustive events.

For example, flip of coin. On a flip of a coin, the flip turns as either Heads or Tails but never both. But together the event of getting a Heads and Tails form a sample space of a single flip of a coin.

In this case also, together the event of a person being overweight or obese forms a sample space of people who are heavier in general.

Thus, the events "overweight" and "obese" exhaustive.

(D)

Mutually exclusive events are those events that cannot occur at the same time.

The events of a person being overweight and obese are mutually exclusive.

5 0
3 years ago
How do I do this equation? Need help please <br> Will mark brainliest
jenyasd209 [6]
The x (the second one) has a one in front of it so 5x *1x=5x so 5x-4 is the answer
4 0
3 years ago
Read 2 more answers
Can I get help please and thank you
Ipatiy [6.2K]

9514 1404 393

Answer:

  a.  0.81

  b.  v = 28000(0.81^n)

  c.  2757.36

Step-by-step explanation:

a. The growth factor is 1 more than the growth rate. Here, the growth rate is -19% (per year), so the growth factor, the multiplier, is ...

  1 -0.19 = 0.81

__

b. The equation sets value equal to the original value multiplied by the growth factor to the power of the number of years:

  value = (original value) × (growth factor)^n

  v = 28000(0.81^n)

__

c. For n=11, this is ...

  v = 28000(0.81^11) ≈ 2757.36

The value of the truck after 11 years is about $2757.

6 0
3 years ago
An athlete runs every day for one week. The following week she runs one mile further than she ran on that day the previous week.
cluponka [151]

Answer:

Buy $HBAR

Step-by-step explanation:

You can find it on exchanges like Bittrex, Voyager, Uphold, and soon enough Coinbase!

5 0
3 years ago
HELP ME ! beautiful people that are good at math
ANTONII [103]
-3(-4y+3) +7y
Expand
12y-9+7y
Add like terms
19y-9
8 0
3 years ago
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