Answer:
1. both boxes 3
2. both boxes 7
3. both boxes 5
4. both boxes 2
5. top box 12 bottom 18
6. top box 9 bottom box 11
7. top box 42 bottom box 60
8. top box 4 bottom box 5
Answer:
52
Step-by-step explanation:
39, 40, 44, 49, 50, 54, 56, 61, 62, 68
39, 40, 44, 49, <u>50, 54,</u> 56, 61, 62, 68
=
= 52
Answer:1.69*10^12 J
Step-by-step explanation:
From figure above, using triangle ratio
485/755.5=y/l. Cross multiplying 485l=755.5y Divide via 485) hence l= 755.5y/485
Consider a slice volume Vslice= (755.5y/485)^2∆y; recall density =150lb/ft^3
Force slice = 150*755.5^2.y^2.∆y/485^2
From figure 2 in the attachment work done for elementary sclice
Wslice= 150.755.5^2.y^2.∆y.(485-y)/485^2
= (150*755.5^2*y^2)(485-y)∆y/485
To calculate the total work we integrate from y=0 to y= 485
Ie W=[ integral of 150*755.5^2 *y^2(485-y)dy/485] at y=0 and y= 485
Integrating the above
W= 150*755.5^2/485[485*y^3/3-y^4/4] at y= 0 and y=485
W= 150*755.5^2/485(485*485^3/3-484^4/4)-(485.0^3/3-0^4/4)
Work done 1.69*10^12joules
Answer:
#6 is 17 days
Step-by-step explanation:
This is how I answered it
1) 2750 = 550 + 125x
2) subtract 550 from each side
2750-550=2200
so the left over equation is:
2200 = 125x
3) divide each side by 125 to get x by itself
2200÷125= 17.6
4) you are left with: x = 17 days
Answer:
C
Step-by-step explanation:
You have to add the whole equation not only a part of it.