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3 years ago

Copy and write the missing factor https://ibb.co/gAKUJA

Mathematics

1 answer:

alexira [117]3 years ago

4 0

I think that the answer would be 5/5

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QUICKK - Which inequality matches the graph?

Marizza181 [45]

$5a < 20 \\ a < \frac{20}{5} \\ a < 4$

5 0

2 years ago

Read 2 more answers

Y= 6(1.013) x x+ 110

Sveta_85 [38]

If u tell me what operation is in between both the x's, then i can solve it for you

5 0

3 years ago

PLEASE I NEED THIS TODAY!!!

Troyanec [42]

Answer:

Option D $y\leq -3x-3$ and $y$

Step-by-step explanation:

step 1

Find the equation of the inequality A

we know that

The solution of the inequality A (dashed line) is the shaded area below the dashed line

The equation of the dashed line is $y=-\frac{1}{2}x+2$

therefore

The equation of the inequality A is $y$

step 2

Find the equation of the inequality B

we know that

The solution of the inequality B (solid line) is the shaded area below the solid line

The equation of the solid line is $y=-3x-3$

therefore

The equation of the inequality B is $y\leq -3x-3$

The system of linear inequalities is

$y\leq -3x-3$ and $y$

6 0

3 years ago

6+[11-{10+2-(8 of 2+1-3×4) }]

Vesna [10]

Answer:

Step-by-step explanation:

Step-by-step explanation:

6+[11-{10+2-(8×2+1-3×4)}]

6+[11-{10+2-(8×2+1-3×4)}]6+[11-{10+2-(12)}

6+[11-{10+2-(8×2+1-3×4)}]6+[11-{10+2-(12)} ]6+[11-[10+2-12}]

6+[11-{10+2-(8×2+1-3×4)}]6+[11-{10+2-(12)} ]6+[11-{10+2-12}]6+[11-{0}]

6+[11-0]

6+[11]

6+11

17 Ans.

7 0

3 years ago

HELP ME QUICK PLEASEEEE solve for x: 2/x-2+7/x^2-4=5/x

Anna35 [415]

$\displaystyle\\\\\frac{2}{x-2}+\frac{7}{x^2-4}=\frac{5}{x}\\\\\frac{^{x+2)}2~~~~~}{x-2}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2(x+2)}{(x-2)(x+2)}+\frac{7}{(x-2)(x+2)}=\frac{5}{x}\\\\\frac{2x+4+7}{x^2-4}=\frac{5}{x}\\\\\frac{2x+11}{x^2-4}=\frac{5}{x}\\\\5(x^2-4)=x(2x+11)\\\\5x^2-20=2x^2+11x\\\\5x^2-2x^2 -11x-20=0$

$\displaystyle\\3x^2-11x-20=0\\\\x_{1,2}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{11\pm\sqrt{121+4\cdot3\cdot20}}{2\cdot3}=\\\\=\frac{11\pm\sqrt{121+240}}{6}=\frac{11\pm\sqrt{361 }}{6}=\frac{11\pm19}{6}\\\\x_1=\frac{11-19}{6}=\frac{-8}{6}\\\\\boxed{\bf x_1=-\frac{4}{3}}\\\\x_2=\frac{11+19}{6}=\frac{30}{6}\\\\\boxed{\bf x_2=5}$

3 0

3 years ago