3x - 5 = 7
3 x 4 = 12
12 - 5 = 7
So x is 4
Answer:
<em>b = 12 cm</em>
Step-by-step explanation:
<u>The Pythagora's Theorem</u>
The area of a square of side length x is

We have three squares, two of which have side lengths of a=5 cm and b= 13 cm.
The combined area of the smaller squares is the same as the area of the largest square. We cannot say at first sight which square is the largest, we'll assume the square of side length of 13 cm is the largest one. Thus:

Where b is the unknown side length.
The above expression corresponds to the Pythagora's Theorem formula. Solving for b:


b = 12 cm
<u>Number of terms = 48</u>
<u>common difference = 1.5</u>
This question involves the concept of Arithmetic Progression.
- The formula for sum of an arithmetic progression series with first and last term given is;
=
(a + l)
where;
a = first term
l = last term
n = number of terms
- From the given sequence, we see that;
first term; a = 4
last term; l = 76
Sum of A.P;
= 1920
- Plugging in relevant values into the sum of an AP formula, we have;
1920 =
(4 + 76)
simplifying this gives;
1920 = 40n
n = 1920/40
n = 48
- Formula for nth term of an AP is;
=
+ (n - 1)d
where;
is first term
d is common difference
n is number of term
is the nth term in question
the 48th term is 76
Thus;
76 = 4 + (48 - 1)d
76 - 4 = 47d
72 = 47d
d = 72/47
d ≈ 1.5
Thus;
Number of terms = 48
common difference = 1.5
Read more at; brainly.com/question/16935540
Answer:
since the formula of a triangle is ab/2 and since there is four simply multiply 3x4 which is 12 and divide by 2 which is 6 and 6x4= 24 and add that tp 9 since the base is just 3x3 which results for an answer of 33.
Step-by-step explanation:
Answer:
There may be fractional solutions in this context.
Step-by-step explanation:
We are given an inequality equation and we have to get a solution to that.
It is, 2s + 36 > 50
⇒ 2s > 50 - 36 {Subtracting 36 from both the sides}
⇒ 2s > 14
⇒ s > 7 {Dividing both sides by 2}
Therefore, solution of this given inequality is s > 7.
Now, the value of s is greater than 7 which may be an integer or a fraction.
So, there may be fractional solutions in this context. (Answer)