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Katarina [22]
3 years ago
11

If the perimeter is 168 and the width is 6 feet longer than thr length what are the dimensions

Mathematics
1 answer:
Ksenya-84 [330]3 years ago
4 0

\bf \textit{perimeter of a rectangle}\\\\ P=2(L+w)~~ \begin{cases} L=length\\ w=width\\ ----------\\ P=168\\ w=\stackrel{\textit{6 feet longer than L}}{L+6} \end{cases}\implies 168=2(L+\stackrel{w}{L+6}) \\\\\\ 84=2L+6\implies 78=2L\implies \cfrac{78}{2}=L\implies \boxed{39=L} \\\\\\ w=39+6\implies \boxed{w=45}

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Determine the value for c on {2, 5} that satisfies the Mean Value Theorem for f(x) = x^2 - 3 / x -1
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Answer:

B. 3.

Step-by-step explanation:

OK lets try again.

The slope of the secant = slope of the tangent at a certain point ( The Mean Value Theorem).

Slope of the secant = f(5) - f(2) / (5 - 2)

= [(25-3) / (5-1)  - (4-3) / (2-1)] / 3

=  (22/4 - 1) / 3

= 9/2 / 3

= 9/6

= 3/2.

The derivative at c = the slope of the tangent at c.

Finding the derivative:

f'(x) =  [2x(x - 1) - (x^2 - 3) ]/ (x - 1)^2    (where x = c).

= (x^2 - 2x + 3)/ (x - 1)^2 = the slope.

So equating the slopes:

(x^2 - 2x + 3) / (x - 1)^2 = 3/2

2x^2 - 4x + 6 = 3x^2 - 6x + 3

x^2 - 2x - 3 = 0

(x - 3)(x + 1) = 90

x = 3 , -1

x can't be -1 because we are working between the values 2 and 5 so

x = c = 3.

4 0
3 years ago
For the sequence 3n - 1, generate the first three terms.
Hunter-Best [27]
3n - 1

When n = 1,

3n - 1 = 3*1 - 1 = 3 -1 = 2

When n = 2,

3n - 1 = 3*2 - 1 = 6 -1 = 5

When n = 3,

3n - 1 = 3*3 - 1 = 9 -1 = 8

Hence, the first three terms are 2, 5 and 8.
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3 years ago
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8 0
3 years ago
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omeli [17]
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8 0
3 years ago
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Aleksandr [31]

Answer:

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