- a • [- b] = c
[a] • [- b] = - c or [-a] • [b] = - c (either one is fine)
[- c] / - b = a
[- c] / [b] = - a
Before I put out my answer, I just want make note that sec() = 1 / cos() and csc () = 1 / sin ()
1) Once you distribute cos()sin() to sec(), the cos() will cancel out with the sec() to make it just sin(), and once cos()sin() is distributed to csc(), the sin() will cancel out with the cos()
2) After doing that you should just be left with sin() + cos()
3) And since no more simplification can be done, that is your answer :D
Mx+b=y ? that’s a formula
Answer:
In a right triangle two of these are merged into the same square, so there are only two distinct inscribed squares. However, an obtuse triangle has only one inscribed square, one of whose sides coincides with part of the longest side of the triangle.
Step-by-step explanation:
The volume of a cylinder is given by

Let
and 
The new volume becomes

So, the new volume is 8 times the original volume. In fact, volume scales linearly with the height and quadratically with the radius.