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Mnenie [13.5K]
3 years ago
8

A 12-foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on the level ground 7 f

eet from the base of the building. How high up the wall does the ladder reach? (Round to the nearest hundredth as needed.)
Mathematics
2 answers:
Elan Coil [88]3 years ago
6 0

Answer: the height that the ladder reaches is 4 feet.

Step-by-step explanation:

The ladder forms a right angle triangle with the building and the ground. The length of the ladder represents the hypotenuse of the right angle triangle. The height, h from the top of the ladder to the base of the building represents the opposite side of the right angle triangle.

The distance from the bottom of the ladder to the base of the building represents the adjacent side of the right angle triangle.

To determine the height that the ladder reaches, h, we would apply Pythagoras theorem which is expressed as

Hypotenuse² = opposite side² + adjacent side²

12² = 7² + h²

144 = 49 + h²

h² = 144 - 49

h² = 95

h = √95

h = 7.45 feet

Airida [17]3 years ago
3 0

Answer:

the ladder reaches up to 9.75 ft. high

Step-by-step explanation:

a^2+b^2=c^2

plug in the numbers

a^2+49=144

then subtract 49 from 144

a^2=95

then sq 95

a=9.75

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What is the probability of rolling a number 2 or less on a dice?
scoray [572]

Answer:

1/3 if it's a standard die with the highest number being 6.

Step-by-step explanation:

3 0
3 years ago
Given the following winning percentages of the teams in a league (for a single year) compute the within-season standard deviatio
Masja [62]

Answer:

(b) 0.251

Step-by-step explanation:

1. Standard deviation equation:

SD=\sqrt{\frac{\sum\limits^N_i {(x_{i}-X)^{2}  } }{N} }

Where X is the mean of the data, and N the amount of data. Then, N=5

2. Estimate the Mean:

X=\frac{0.750+0.750+0.200+0.600+0.200}{5}=\frac{2.5}{5}=0.5\\

3. Caclulate Standard deviation:

SD=\sqrt{\frac{{(0.750-0.500)^{2}+(0.750-0.500)^{2}+(0.200-0.500)^{2}+(0.600-0.500)^{2}+(0.200-0.500)^{2}  } }{5} }

SD=\sqrt{\frac{0.315}{5} }=\sqrt{0.063}\\SD=0.251

7 0
3 years ago
What is the product of seven and eight decreased by “x” if x =15?
jekas [21]

Answer:

0

Step-by-step explanation:

product is another word for +

decreased is another word for -

____________________________

(7 + 8) - x

so

(7+8) - 15

15 - 15

= 0

7 0
2 years ago
Read 2 more answers
Complete the square to solve the equation below.
sasho [114]
Hello there!

x² + x = 7/4
x² + - 7/4 = 0

Now we gonna use the quadratic formula to find x
a= 1
b=1
c = -1.75

x = -b+/-√b² -4ac all of them divide by 2a
x = -(1)+/-√(1)² - (4)(1)(-1.75) all of them divide by 2(1)
x= -1+/-√8 all of them divide by 2
x = -1/2 + √2 or x = -1/2 - √2

The correct option is option C

I hope that helps!
4 0
3 years ago
Regular hexagon ABCDEF has vertices at A(4, 4!3), B(8, 4!3), C(10, 2!3), D(8, 0), E(4, 0) and F(2, 2!3).
marissa [1.9K]

Since the given hexagon is a regular hexagon all it's sides will be of equal length. Now, we know that the Area of any regular hexagon is given by:

A=\frac{3\sqrt{3}}{2} a^2

Where A is the area of the regular hexagon

a is the side length of the regular hexagon

Also, it's Perimeter is given by:

P=6a

Thus, all that we need to do is to find the side length of any one of the sides and to do that let us have a look at at the data of vertices points given and find out which points are definitely adjacent to each other and are also easy to calculate.

A quick search will yield that D(8, 0) and E(4, 0) are definitely adjacent to each other.

Please check the attached file here for a better understanding of the diagram of the original regular hexagon. Points D and E indeed are adjacent to each other.

Let us now find the distance between the points D and E using the distance formula which is as:

d=\sqrt{(x_1-x_2)^2+(y_1-y_2)^2}

Where d is the distance.

(x_1,y_1) and (x_2,y_2) are the coordinates of points D and E respectively. (please note that interchanging the values of the coordinates will not alter the distance d)

Applying the above formula we get:

d=\sqrt{(8-4)^2+(0-0)^2} =\sqrt{4^2}=4

\therefore d=4

We know that this distance is the side length of the given regular hexagon.

\therefore d=a=4

Now, if the sides of the given regular polygon are reduced by 40%, then the new length of the sides will be:

a_{small}=4-\frac{40}{100}\times 4=2.4

Thus, the area of the smaller hexagon will be:

A_{small}=\frac{3\sqrt{3}}{2} a_{small}^2=\frac{3\sqrt{3}}{2} (2.4)^2\approx14.96 unit squared

and the new smaller perimeter will be:

P_{small}=6a_{small}=6\times 2.4=14.4 unit

Which are the required answers.

5 0
3 years ago
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