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ziro4ka [17]
3 years ago
6

What is the y-coordinate of the point that divides the directed line segment from J to K into a ratio of 5:1? –8 –5 0 6

Mathematics
1 answer:
Alex17521 [72]3 years ago
4 0
I believe it is “0” ‼️‼️
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suppose a parabola has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1). Write the eq
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Answer:

<h3>            f(x) = - 3(x + 8)² + 2</h3>

Step-by-step explanation:

f(x) = a(x - h)² + k   - the vertex form of the quadratic function with vertex    (h, k)

the<u> axis of symmetry</u> at<u> x = -8</u> means h = -8

the <u>maximum height of 2</u> means  k = 2

So:

f(x) = a(x - (-8))² + 2

f(x) = a(x + 8)² + 2   - the vertex form of the quadratic function with vertex   (-8, 2)

The parabola passing through the point (-7, -1) means that if x = -7 then        f(x) = -1

so:

    -1 = a(-7 + 8)² + 2

 -1 -2 = a(1)² + 2 -2

      -3 = a

Threfore:

The vertex form of the parabola which has an axis of symmetry at x = -8, a maximum height of 2, and passes through the point (-7, -1) is:

                                 <u>f(x) = -3(x + 8)² + 2</u>

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Answer: x=-2+2 sqrt 6 divided by 5

Hoor this helps

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

x/4 - 7 = y

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