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Yuliya22 [10]
3 years ago
6

Are right triangles always congruent

Mathematics
1 answer:
Darya [45]3 years ago
6 0
All right triangles have two legs<span>, which may or may not be congruent. The legs of a right triangle meet at a </span>right angle<span>. The other side of the triangle (that does not form any part of the right angle), is called the </span>hypotenuse<span> of the right triangle.</span>
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Mrrafil [7]
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Also, the table has <u>4 legs</u>

The number of the big cats is 7 *7 =49 (big cats)

For every big cat we have ---> 49 * 4= <u>196 legs</u>

For every big cat we have 7 small cats which means --> 49 * 7= 343 (small kittens)

The number of legs for small kittens is 343 * 4 = <u>1372 legs</u>

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5 0
2 years ago
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FinnZ [79.3K]

Answer:

-10.

Step-by-step explanation:

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2 years ago
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An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
5.26 x 10^6 in standard form <br><br>PLS HURRY I ONLY GOT 10 MINS LEFT
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Answer:

5,260,000

Step-by-step explanation:

I don't know if this is right - you can try it!!

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