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3 years ago

6

Are right triangles always congruent

1 answer:

Darya [45]3 years ago

6 0

All right triangles have two legs<span>, which may or may not be congruent. The legs of a right triangle meet at a </span>right angle<span>. The other side of the triangle (that does not form any part of the right angle), is called the </span>hypotenuse<span> of the right triangle.</span>

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Emerson struck out 112 times in 350 at-bats.

Veseljchak [2.6K]

Emerson struck out 112 times out of the total of 350 times. therefore, this can be represented as the fraction 112/350, which can be simplified to 8/25.

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2 years ago

Evaluate 5r-8.35s when r=12 and s=4

balu736 [363]

Answer: 26.6

Step-by-step explanation:

r = 12 5(12) = 60 | s = 4 8.35(4) = 33.4 | Now subtract both total number = 33.4 - 60 = 26.6

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3 years ago

the weight M of an object on Mars varies directly as it’s weight E on Earth. A person who weighs 95 lb on Earth weighs 38 lb on

lorasvet [3.4K]

Answer:

A 100 lb person will weight 40 lb on Mars

Step-by-step explanation:

Given:

Weight on Mars directly varies as its weight on earth.

Let weight on Mars be = $M$

Let weight on Earth be = $E$

Its known that:

$M$ ∝ $E$

Thus

$M=kE$

where $k$ is constant of proportionality.

when $E=95\ lb$ , then $M=38\ lb$

thus, we have

$38=k(95)$

dividing both sides by 95.

$\frac{38}{95}=\frac{k(95)}{95}$

∴ $k=\frac{38}{95}$

Thus when $E= 100$ , $M$ would be calculated as

$M=\frac{38}{95}\times 100$

$M=\frac{3800}{95}$

∴ $M=40\ lb$ (Answer)

∴ A 100 lb person will weight 40 lb on Mars.

8 0

3 years ago

¿Como se realizan ecuaciones de primer grado?

Law Incorporation [45]

5^0=1

Any exponent to zero power equals 1

7 0

3 years ago

Mr.Williams, a parking lot owner, sold 20% of his lot to his neighbor. Later that year he sold 20% of the remainder of his lot t

riadik2000 [5.3K]

Answer: He still owns 64% of the Mr.Williams' original parking.

Step-by-step explanation:

Let x = Area of the original parking plot.

First he sold 20% of his lot to neighbor .

Sold plot = 20% of x = 0.20x [Replace 'of' by '×' and divide number by 100 to remove %]

Reminder= x-0.20x= (1-0.20)x=0.80x

Again he sold 20% of the remainder .

Sold plot = 20% of (0.80x) = 0.20 (0.80x)

= 0.16x

Remainder plot = 0.80x-0.16x= 0.64x

Percent of Mr.Williams' original parking lot does he still own = $\dfrac{0.64x}{x}\times100=64\%$

Hence, he still owns 64% of the Mr.Williams' original parking.

4 0

2 years ago