Any number inside the modulus sign becomes positive. This means 
and so we have,
Solving these gives us
However if we check the second solution in the original equation we obtain 
. This is false and so 
can't be a solution.
Therefore the only solution is 
.
(Note: I'm not sure why the second solution didn't work but when there's a modulus sign involved it always pays to check your final answers to be sure. I'll have a think about it but in case you find out before I do, I'd be interested to know in the comments.)
Answer:
see below
Step-by-step explanation:
The exponent rules that apply are ...
(a^b)(a^c) = a^(b+c)
a^-b = (1/a)^b
(a^b)^c = a^(b·c)
_____
These let you rewrite the given function as ...
f(x) = (3^(2x))(3^1) = 3(3^(2x)) = 3(3^2)^x = 3·9^x
and
f(x) = 3^(2x+1) = (3^-1)^(-(2x+1)) = (1/3)^-(2x+1)
Answer:
a . domain 5,0,7,9,0
range -2,-2,-4,8,2
b. domain 2,4,8,9
range 1,2,4,11
Step-by-step explanation:
<h3>a is not a function</h3>
because function is a relationship in which each domain element occurs only once.
<h3>b is a function</h3>
Answer:
Nicole is correct
Step-by-step explanation:
They need to get the 3y on one side of the equal sign and the known numbers on the other side. To do this, they must subtract the 4 from both sides.
Answer:kk
Step-by-step explanation:
