Given:
The given sequence is:

To find:
The recursive formula for
, the nth term of the sequence.
Solution:
We have,

Here, the first term is 5.



The common difference is -7.
The recursive formula for the nth term of the sequence is

Where,
is the common difference.
Putting
in the above formula, we get


Therefore, the recursive formula for the nth term of the sequence is
.
The nature of a graph, which has an even degree and a positive leading coefficient will be<u> up left, up right</u> position
<h3 /><h3>What is the nature of the graph of a quadratic equation?</h3>
The nature of the graphical representation of a quadratic equation with an even degree and a positive leading coefficient will give a parabola curve.
Given that we have a function f(x) = an even degree and a positive leading coefficient. i.e.
The domain of this function varies from -∞ < x < ∞ and the parabolic curve will be positioned on the upward left and upward right x-axis.
Learn more about the graph of a quadratic equation here:
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Answer:
x = −10 and x = 4
Step-by-step explanation:
x2 + 6x = 40
Subtract 40 from each side
x^2 + 6x -40 =0
Factor, what 2 numbers multiply to -40 and add to 6
10 * -4 = -40 10+-4 = 6
(x+10) (x-4) = 0
Using the zero product property
x+10 =0 x-4=0
x=-10 x=4
Answer: the answer has to be number 3if I’m not mistaking
Step-by-step explanation:
I took this test last year
Answer: it might be 8
Step-by-step explanation: Write a distance formula: x^2 - x^1
substituted -3.8, 4.2 into x^2 - x^1 and u will get 4.2 + 3.8 and u will calculate and it gets 8
I hope its right