Answer:
x= 6
Step-by-step explanation:
Answer:
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Step-by-step explanation:
Given the data in the question;
If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is?
dA/dt = rate in - rate out
first we determine the rate in and rate out;
rate in = 3pound/gallon × 5gallons/min = 15 pound/min
rate out = A pounds/1000gallons × 5gallons/min = 5Ag/1000pounds/min
= 0.005A pounds/min
so we substitute
dA/dt = rate in - rate out
dA/dt = 15 - 0.005A
Therefore, If A(t) represents the amount of salt in the tank at time t, the correct differential equation for A is is dA/dt = 15 - 0.005A
Option C) dA/dt = 15 - 0.005A is the correction Answer
Answer:
73 y/o
Step-by-step explanation:
Multiples of 9 between 50 and 80:
54 63 72 now add 1
55 64 73 now divide by 4 to find which has remainder of 1
73 y/o
Given:
Two planks are each 1.5 m long.
One plank is 2.5m long.
To find:
The total length of all the three planks.
Solution:
Two planks are each 1.5 m long. So,
First plank = 1.5 m
Second plank = 1.5 m
One plank is 2.5m long. So,
Third plank = 2.5 m
Now, the total length of all the three planks is
![\text{Total length}=\text{First plank + Second plank + Third plank}](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20length%7D%3D%5Ctext%7BFirst%20plank%20%2B%20Second%20plank%20%2B%20Third%20plank%7D)
![\text{Total length}=1.5+1.5+2.5](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20length%7D%3D1.5%2B1.5%2B2.5)
![\text{Total length}=5.5](https://tex.z-dn.net/?f=%5Ctext%7BTotal%20length%7D%3D5.5)
Therefore, the total length of all the three planks is 5.5 m.