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Digiron [165]
3 years ago
15

The quotient of a number and 9. Algebraic expression.

Mathematics
1 answer:
vlada-n [284]3 years ago
8 0
The quotient of a number and nine will be: 9n
x/9

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Solve for the unknown variables
malfutka [58]

Answer:

This term is known as algebra.

Step-by-step explanation:

Algebra is all about solving for unknown values. Of course, in the primary phrase (question) it says, "Solve for the unknown variables," and the unknowns are unknown variables that have values that are unknown and must be found through algebraic processes.  

<h2>What is an "algebra" in mathematics?</h2>

Variables like as x, y, and z are coupled with mathematical operations such as addition, subtraction, multiplication, and division to generate a meaningful mathematical statement. An algebraic expression is as basic as 2x + 4 = 8. Algebra is concerned with symbols, and these symbols are connected to one another through operators. It is more than just a mathematical concept; it is a skill that we all have without even realizing it. Understanding algebra as a concept is more important than solving equations and achieving the proper solution since it applies to all other disciplines of mathematics that you will learn or have previously learned.

<h3>What is Algebra?</h3>

Algebra  is a field of mathematics that works with symbols and the mathematical operations that may be performed on them. These symbols, which have no set values, are referred to as variables. We frequently encounter values that change in our real-life issues. However, there is a continual requirement to represent these changing values. In algebra, these values are frequently represented by symbols such as x, y, z, p, or q, and these symbols are referred to as variables. Furthermore, these symbols are subjected to different mathematical operations such as addition, subtraction, multiplication, and division in order to determine the values. 3x + 4 = 28. Operators, variables, and constants are used in the algebraic formulas above. The integers 4, 28, and x are constants, and the arithmetic operation of addition is done. Algebra is a branch of mathematics concerned with symbols and the mathematical operations that may be applied to them. Variables are symbols that do not have predefined values. In our daily lives, we regularly face values that shift. However, there is a constant need to express these shifting values. These values are usually represented in algebra by symbols such as x, y, z, p, or q, and these symbols are known as variables. Furthermore, in order to ascertain the values, these symbols are subjected to various mathematical operations such as addition, subtraction, multiplication, and division. 3x + 4 = 28. The algebraic formulae above make use of operators, variables, and constants. The constants are the numbers 4, 28, and x, and the arithmetic operation of addition is done.

<h3>Branches of Algebra</h3>

The use of many algebraic expressions lessens the algebraic complexity. Based on the usage and complexity of the expressions, algebra may be separated into many branches, which are listed below:

Pre-algebra: The basic methods for expressing unknown values as variables help in the formulation of mathematical assertions. It facilitates in the transition of real-world problems into mathematical algebraic expressions. Pre-algebra entails creating a mathematical expression for the given problem statement.

Primary algebra: Elementary algebra is concerned with resolving algebraic expressions in order to arrive at a viable solution. Simple variables such as x and y are expressed as equations in elementary algebra. Based on the degree of the variable, the equations are classed as linear, quadratic, or polynomial. The following formulae are examples of linear equations: axe + b = c, axe + by + c = 0, axe + by + cz + d = 0. Primary algebra can branch out into quadratic equations and polynomials depending on the degree of the variables.

<h3>Algebraic Expressions</h3>

An algebraic expression is made up of integer constants, variables, and the fundamental arithmetic operations of addition (+), subtraction (-), multiplication (x), and division (/). An algebraic expression would be 5x + 6. In this situation, 5 and 6 are constants, but x is not. Furthermore, the variables can be simple variables that use alphabets like x, y, and z, or complicated variables that use numbers like

x^2,x^3,x^n,xy,x^2y,

and so forth. Algebraic expressions are sometimes known as polynomials. A polynomial is a mathematical equation that consists of variables (also known as indeterminates), coefficients, and non-negative integer variable exponents. As an example,

5x^3+4x^2+7x+2=0

Any equation is a mathematical statement including the symbol 'equal to' between two algebraic expressions with equal values. The following are the many types of equations where we employ the algebra idea, based on the degree of the variable: Linear equations, which are stated in exponents of one degree, are used to explain the relationship between variables such as x, y, and z. Quadratic Formulas: A quadratic equation is usually written in the form

ax^2+bx+c=0,

7 0
1 year ago
Help evaluating the indefinite integral
Dafna11 [192]

Answer:

\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

General Formulas and Concepts:
<u>Calculus</u>

Differentiation

  • Derivatives
  • Derivative Notation

Derivative Property [Multiplied Constant]:
\displaystyle (cu)' = cu'

Derivative Property [Addition/Subtraction]:
\displaystyle (u + v)' = u' + v'
Derivative Rule [Basic Power Rule]:

  1. f(x) = cxⁿ
  2. f’(x) = c·nxⁿ⁻¹

Integration

  • Integrals

Integration Rule [Reverse Power Rule]:
\displaystyle \int {x^n} \, dx = \frac{x^{n + 1}}{n + 1} + C

Integration Property [Multiplied Constant]:
\displaystyle \int {cf(x)} \, dx = c \int {f(x)} \, dx

Integration Methods: U-Substitution and U-Solve

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify given.</em>

<em />\displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx

<u>Step 2: Integrate Pt. 1</u>

<em>Identify variables for u-substitution/u-solve</em>.

  1. Set <em>u</em>:
    \displaystyle u = 4 - x^2
  2. [<em>u</em>] Differentiate [Derivative Rules and Properties]:
    \displaystyle du = -2x \ dx
  3. [<em>du</em>] Rewrite [U-Solve]:
    \displaystyle dx = \frac{-1}{2x} \ du

<u>Step 3: Integrate Pt. 2</u>

  1. [Integral] Apply U-Solve:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-x}{2x\sqrt{u}}} \, du
  2. [Integrand] Simplify:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \int {\frac{-1}{2\sqrt{u}}} \, du
  3. [Integral] Rewrite [Integration Property - Multiplied Constant]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \frac{-1}{2} \int {\frac{1}{\sqrt{u}}} \, du
  4. [Integral] Apply Integration Rule [Reverse Power Rule]:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = -\sqrt{u} + C
  5. [<em>u</em>] Back-substitute:
    \displaystyle \int {\frac{x}{\sqrt{4 - x^2}}} \, dx = \boxed{ -\sqrt{4 - x^2} + C }

∴ we have used u-solve (u-substitution) to <em>find</em> the indefinite integral.

---

Learn more about integration: brainly.com/question/27746495

Learn more about Calculus: brainly.com/question/27746485

---

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Integration

5 0
2 years ago
6th grade math help me pleaseeee
Furkat [3]

Answer:

I think it's the top left one

Step-by-step explanation:

8 0
2 years ago
Read 2 more answers
What is the ratio of the area of the inner square to the area of the outer square?
Anastasy [175]

Answer:

\frac{(a-b)^2+b^2}{a^2}

Step-by-step explanation:

Since, By the given diagram,

The side of the inner square = Distance between the points (0,b) and (a-b,0)

=\sqrt{(a-b-0)^2+(0-b)^2}

=\sqrt{(a-b)^2+b^2}

Thus the area of the inner square = (side)²

=(\sqrt{(a-b)^2+b^2})^2

=(a-b)^2+b^2\text{ square cm}

Now, the side of the outer square = Distance between the points (0,0) and (a,0),

=\sqrt{(a-0)^2+0^2}

=\sqrt{a^2}=a

Thus, the area of the outer square = (side)²

=a^2\text{ square cm}

Hence, the ratio of the area of the inner square to the area of the outer square

=\frac{(a-b)^2+b^2}{a^2}

4 0
2 years ago
Read 2 more answers
Suppose you have $23,000 that you are going to invest at a 7% interest rate compounded quarterly. According to the compound inte
andrew11 [14]
YAAS! I literally learned this just a few weeks ago. (I am not actually a high school senior) First, convert 7% to a decimal, which is 0.07. Then multiply 0.07 by 23,000, giving you 1,610. This is your unit rate. I will though, need you to be more specific on "compounding quarterly" because I actually do not know what that means.
5 0
3 years ago
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