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s344n2d4d5 [400]
3 years ago
15

Daren and Josh are pretty good free throw shooters. Daren makes 75% of the free throws he attempts. Josh makes 80% of his free t

hrows. Suppose we take separate random samples of 50 free throws each from Daren and Josh, and record the proportion of free throws that are made by each. Which of the following best describes the sampling distribution of PD - Pj? (A) Strong skew, with mean -0.05 and standard deviation 0.083 (B) Approximately normal, with mean -0.05 and standard deviation 0.083 (C) Shape cannot be determined, with mean -0.05 and standard deviation 0.083 (D) Strong skew, with mean -0.05 and standard deviation 0.118 (E) Approximately normal, with mean -0.05 and standard deviation 0.118
Mathematics
1 answer:
snow_lady [41]3 years ago
5 0

Answer:

Djud

Step-by-step explanation:

Ueud

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The ammunition storage room has 10 feet between the floor and the ceiling. Each box of ammunition is 10 feet tall. Each crate of
KIM [24]

Answer:

the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.

Step-by-step explanation:

i) the maximum number of crates that can be stacked between the floor and ceiling

\frac{height \hspace{0.1cm} of  \hspace{0.1cm} ammunition \hspace{0.1cm} box}{height \hspace{0.1cm} of  \hspace{0.1cm} each \hspace{0.1cm} crate}  = \frac{10 \hspace{0.1cm}  feet}{12 \hspace{0.1cm}  inches}  =  \frac{10 \times 12  \hspace{0.1cm} inches }{12  \hspace{0.1cm} inches}  = 10 \hspace{0.1cm}  crates

where 1 foot  = 12 inches

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2 years ago
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