Can someone help plsss asap

Mathematics

1 answer:

Bad White [126]3 years ago

4 0

Answer:

6/18 x 4/6

Step-by-step explanation:

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You have drawn a simple random sample of 36 college students, asking each student how much rent they pay per month. You obtain a

Karo-lina-s [1.5K]

Answer:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.80 and 579.20]

Step-by-step explanation:

Information given

$\bar X=573$ represent the sample mean

$\mu$ population mean (variable of interest)

s=22 represent the sample standard deviation

n=36 represent the sample size

Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

The degrees of freedom are given by:

$df=n-1=36-1=35$

The Confidence level is 0.90 or 90%, the significance would be $\alpha=0.1$ and $\alpha/2 =0.05$ , and the critical value for this case would be $t_{\alpha/2}=1.690$

And replacing we got:

$573-1.690\frac{22}{\sqrt{36}}=566.8033$

$573+1.690\frac{22}{\sqrt{36}}=579.1967$

And the 90% confidence interval would be between [566.8033 and 579.1967]

6 0

3 years ago

Suponha que uma variável assume os valores: 11 – 8 – 7 – a – 16 – 10 Determine a de modo que a média aritmética seja igual 11.

Elenna [48]

Answer:

a = 14

Step-by-step explanation:

The mean is the sum of the values divided by the number of values.

$\begin{array}{rcl}\text{Mean}&= &\dfrac{11 + 8 + 7 + a + 16 + 10}{6}\\\\\dfrac{52 + a}{6}& = & 11\\52 + a & = & 66\\a & = & 66 - 52\\& = & \mathbf{14}\\\end{array}$