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3 years ago

13

Can a prime number be a multitude of any other number

2 answers:

fredd [130]3 years ago

7 0

Nope

I hope this helps and have a wonderful day filled with joy!!

wariber [46]3 years ago

3 0

No.
a prime number is a number with only 1 and itself as factors.

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Tom has 7/8 gallons of paint. He used 1/2 gallon of paint on a project. He uses the steps to show how much paint he had when he

WINSTONCH [101]

He made his mistake in Step 2. Tom should have subtracted 4/8 instead of 1/8. The mistake is that he was not consistent when he multiplied Denominators (bottom number) must be the same when handling fractions so Tom must multiply both the numerator and denominator by the SAME number to balance it out. 1/2 x 4/4= 4/8. Subtract. 7/8 - 4/8= 3/8. Tom has 3/8 of a gallon of paint leftover.

4 0

3 years ago

Read 2 more answers

Volgvan

The arc angle AC is measured as 55 degrees.

<h3>How to find arc angle?</h3>

If two secant intersect in the exterior of a circle, then the measure of the angle formed is half the positive difference of the arcs intercepted.

Therefore, the secants intersect outside the circle at point E.

The arc angle AC can be found as follows:

Therefore,

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

arc angle AC = x

arc angle BD = 23 degrees.

m∠BED = 16 degrees.

m∠BED = 1 / 2 (arc angle AC - arc angle BD)

16 = 1 / 2 (x - 23)

16 = 1 / 2x - 23 / 2

16 + 11.5 = 0.5x

27.5 = 0.5x

x = 27.5 / 0.5

x = 55 degrees.

Therefore,

arc angle AC = 55 degrees.

learn more on arc angle here: hhttps://brainly.com/question/23117081

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7 0

1 year ago

A production process is checked periodically by a quality control inspector. the inspector selects simple random samples of 30 f

777dan777 [17]

Answer:

Population Mean = 2.0

Population Standard deviation = 0.03

Step-by-step explanation:

We are given that the inspector selects simple random samples of 30 finished products and computes the sample mean product weight.

Also, test results over a long period of time show that 5% of the values are over 2.1 pounds and 5% are under 1.9 pounds.

Now, mean of the population is given the average of two extreme boundaries because mean lies exactly in the middle of the distribution.

So, Mean, $\mu$ = $\frac{1.9+2.1}{2}$ = 2.0

Therefore, mean for the population of products produced with this process is 2.

Since, we are given that 5% of the values are under 1.9 pounds so we will calculate the z score value corresponding to a probability of 5% i.e.

z = -1.6449 {from z % table}

We know that z formula is given by ;

$Z = \frac{Xbar - \mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

-1.6449 = $\frac{1.9 - 2.0}{\frac{\sigma}{\sqrt{n} } }$ ⇒ $\frac{\sigma}{\sqrt{n} } = \frac{-0.1}{-1.6449}$

⇒ $\sigma =$ 0.0608 * $\sqrt{30}$ {as sample size is given 30}

⇒ $\sigma$ = 0.03 .

Therefore, Standard deviation for the population of products produced with this process is 0.0333.

7 0

4 years ago

PLEASE HELP<br><br> A.12.5<br> B.15.7<br> C.16<br> D.16.5

Mashutka [201]

60.7 because you add all the sides together

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3 years ago

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Sidana [21]

are your O's different sizes? or is it just my eyes?

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3 years ago