Can a prime number be a multitude of any other number

There are 20 girls and 26 boys on the tennis team,what is the ratio of numbers of girls to the total numbers of players on the t

Yuri [45]

Answer:

20:46 or 20 to 46

Step-by-step explanation:

There are 20 girls on the team so theres your first number then you add the girls and boys to get the total number of players (46) and write out your ratio

5 0

3 years ago

Read 2 more answers

I’m stumped, can anyone please help me understand this

rodikova [14]

Answer:

B. Store T sells apples at the lowest rate

Step-by-step explanation:

Store R sells apples at $1.20 per pound.

Store S sells 4 pounds of apples at $5.00.

Store T sells 3 pounds of apples at $3.48.

To find the answer, you have to find the unit price for both Store S and Store T.

For Store S: 4 pounds = $5. Divide the cost by the pounds. This will give us $1.25 per pound.

For Store T: 3 pounds = $3.48. Same thing as Store S, divide the cost by the number of pounds. This will give us 1.16 per pound.

Now, we know the unit prices for each store. It's time to answer the question.

A. Store R sells apples at the lowest rate.

This is incorrect because the store that sells the apples at the lowest rate is Store T.

B. Store T sells the apples at the lowest rate.

This answer is correct, but I'll also take a look at the other two

C. Store S charges a lower rate for apples than Store T.

Again, this is incorrect because Store T sells apples at the lowest rate.

D. Store T charges the same rate for apples as Store R.

Nope, Store T sells the apples at a lower rate than Store R.

This means your answer will be B. Store T sells apples at the lowest rate.

<h2>I hope this helped you understand the question!</h2>

6 0

3 years ago

a. Fill in the midpoint of each class in the column provided. b. Enter the midpoints in L1 and the frequencies in L2, and use 1-

Tresset [83]

Answer:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Using the frequency distribution, I found the mean height to be 70.2903 with a standard deviation of 3.5795

Step-by-step explanation:

Given

See attachment for class

Solving (a): Fill the midpoint of each class.

Midpoint (M) is calculated as:

$M = \frac{1}{2}(Lower + Upper)$

Where

$Lower \to$ Lower class interval

$Upper \to$ Upper class interval

So, we have:

Class 63-65:

$M = \frac{1}{2}(63 + 65) = 64$

Class 66 - 68:

$M = \frac{1}{2}(66 + 68) = 67$

When the computation is completed, the frequency distribution will be:

$\begin{array}{ccc}{Midpoint} & {Class} & {Frequency} & {64} & {63-65} & {1} & {67} & {66-68} & {11} & {70} & {69-71} & {8} &{73} & {72-74} & {7} & {76} & {75-77} & {3} & {79} & {78-80} & {1}\ \end{array}$

Solving (b): Mean and standard deviation using 1-VarStats

Using 1-VarStats, the solution is:

$\bar x = 70.2903$