<img src="https://tex.z-dn.net/?f=%5Csqrt%7B2x%2B5%7D%20%20-4%3D3" id="TexFormula1" title="\sqrt{2x+5} -4=3" alt="\sqrt{2x+5}

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forsale [732]

3 years ago

-4=3" align="absmiddle" class="latex-formula">

Mathematics

1 answer:

Likurg_2 [28]3 years ago

6 0

Answer:

$x = 22$

Step-by-step explanation:

Step 1: Add 4 to both sides

$\sqrt{2x + 5}-4+4=3+4$

$\sqrt{2x+5}=7$

Step 2: Square both sides

$(\sqrt{2x+5})^2 = 7^2$

$2x+5 = 49\\$

Step 3: Subtract 5 from both sides

$2x + 5 - 5 = 49 - 5\\$

$2x = 44$

Step 4: Divide both sides by 2

$2x / 2 = 44 / 2\\$

$x = 22$

Answer: $x = 22$

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Answer:

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Step-by-step explanation:

The correct question is

Find three consecutive integers such that the sum of the first, twice the second and three times the third is -76. What is the number?

Let

x ----> the first consecutive integer

x+1 ---> the second consecutive integer

x+2 ---> the third consecutive integer

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therefore

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