Here's the general formula for bacteria growth/decay problems
Af = Ai (e^kt)
where:
Af = Final amount
Ai = Initial amount
k = growth rate constant
<span>t = time
But there's another formula for a doubling problem.
</span>kt = ln(2)
So, Colby (1)
k1A = ln(2) / t
k1A = ln(2) / 2 = 0.34657 per hour.
So, Jaquan (2)
k2A = ln(2) / t
<span>k2A = ln(2) /3 = 0.23105 per hour.
</span>
We need to use the rate of Colby and Jaquan in order to get the final amount in 1 day or 24 hours.
Af1 = 50(e^0.34657(24))
Af1 = 204,800
Af2 = 204,800 = Ai2(e^0.23105(24))
<span>Af2 = 800</span>
Answer:
11.5 kg
Step-by-step explanation:
Is means equals and of means multiply
50% * 23 = W
Change to decimal form
.50 * 23 =W
11.5 = W
1/2(-14x + 14) + 14x
<em><u>Distributive property.</u></em>
-7x + 7 + 14x
<em><u>Combine like terms.</u></em>
7x + 7 (This is the simplified answer.)
Answer:
1.) If two angles have equal measures, then the measure of each is 28 degrees.
Step-by-step explanation:
The converse of a statement simply swaps the positions of the "if" and "then" clauses. Without any modification for clarity or readability, the converse would be ...
if <em>two angles are equal in measure</em>, then <em>each of the two angles has a measure of 28 degrees</em>.
The formula for this is
. If the diameter is 8 the radius is 4, so filling in accordingly we have
and
which is
and when you multiply in 3.14 you get that A = 401.92 or B above.
