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romanna [79]
3 years ago
12

Please help is this answer are right, number 1 and question #2

Mathematics
1 answer:
VladimirAG [237]3 years ago
7 0
Yes. They are both right.
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PLEASE HELP !! ILL GIVE BRAINLIEST *EXTRA 40 POINTS* DONT SKIP :(( .!
Llana [10]

Define your two QUESTIONS

Write your system of EQUATIONS

SOLVE the system of equations.

Find the SOLUTION to the question being asked.

6 0
3 years ago
Rewrite 2x^2+13x+26/x+4 in the form q(x)+r(x)/b(x) . Then find q(x) and r(x).
natulia [17]
We are dividing the polynomial 2x^{2} +13x+26 by x+4

notice that 2x^{2} is x times 2x,

so if we multiply (x+4) by 2x, which gives us 2 x^{2} +8x, we can 'separate' one 2 x^{2} +8x from 2x^{2} +13x+26  to get the following simplification:

\frac{2x^{2} +13x+26}{x+4}= \frac{ 2x^{2}+8 x}{x+4} + \frac{5x+26}{x+4}=2x+ \frac{5x+26}{x+4}

similarly we notice that 5x is x times 5, so if we multiply (x+4) by 5, we get 5x+20 so we can rewrite 

\frac{5x+26}{x+4}= \frac{5x+20}{x+4}+  \frac{6}{x+4}=5+\frac{6}{x+4}

\frac{6}{x+4} can not be simplified any further since the degree of 6, is smaller than the degree of x+4

combining our work, we have:

\frac{2x^{2} +13x+26}{x+4}=2x+5+\frac{6}{x+4}

Answer:

q(x)= 2x+5
r(x)=6
b(x)=x+4


Remark: we can solve the problem by long division or the division algorithm as well.
6 0
4 years ago
Read 2 more answers
A quarter, a nickel,and a penny are flipped. Find the probability of each of the following:-
morpeh [17]
The probability<span> of an event is the measure of the chance that the event will occur as a result of an experiment. The </span>probability<span> of an event A is the number of ways event A can occur divided by the total number of possible outcomes.
a.) since each coin has 50% chance to have heads
(1/2) x  (1/2) = 1/4 probability </span><span>The penny and nickel shows head

b.) </span><span>All these coins land the same way
</span>(1/2) x  (1/2) x  (1/2) = 1/8
3 0
4 years ago
Simplify 4(x-y)-8(-7x+6y)
aliya0001 [1]
The answer is 60x-52y

Hope that helped!
8 0
3 years ago
Read 2 more answers
If a space of 18 inches is allowed for each person, how many persons can be seated in a row of bleacher seats 90 feet long?
REY [17]

Answer:

31 people

Step-by-step explanation:

think of it like a line,

first person at zero then add 3 feet per person so...

1 + 90/3 = 31 people

kinda funny that the problem isnt accounting for the size of the people

6 0
4 years ago
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