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Dominik [7]
3 years ago
7

To deliver mulch, lawn and gardens charge $30 per cubic yard of mulch plus a $30 delivery fee. Yard depot charges $25 per cubic

yard of mulch plus an extra $55 delivery fee. For how many cubic yards will the cost be the same? What will the cost be?
Mathematics
1 answer:
Natasha_Volkova [10]3 years ago
3 0
So lawn and gardens will be 55 for one square yard and yard depot will be 80.
lawn and gardens costs 5 more for each cubic yard
80- 55 to get the difference in costs
25 is the difference 
25/5 
5 extra yards will be needed 
proof:
lawn and garden = l
yard depot = y
l=30x +30
y=25x+55
30(5) +30
150+30
180

25(5) + 55 
125 + 55
180

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Lanette drove 248 miles in 4 hours at that rate , how many hours will it tak her to drive an additional 93 miles.
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4 0
3 years ago
The quotient of 9 times an unknown number and 16 is 81. What is the value of the unknown number?
riadik2000 [5.3K]
Quotient means division.

(9x)/16 = 81

9x = 1296

x = 144

The unknown number is 144.
5 0
3 years ago
Read 2 more answers
Let
Digiron [165]

What I gather from the question is that X has second moment E(X^2)=81 and variance V(X) = 58, and you're asked to find the expectation and variance of the random variable Y=2X+10.

From the given second moment and variance, we find the expectation of X :

V(X) = E(X^2) - E(X)^2 \implies E(X) = \sqrt{E(X^2) - V(X)} = \sqrt{23}

Expectation is linear, so

E(Y) = E(2X+10) = 2 E(X) + 10 = \boxed{2\sqrt{23} + 10}

Using the same variance identity, we have

V(Y) = V(2X+10) = E((2X+10)^2) - E(2X+10)^2

and

E((2X+10)^2) = E(4X^2 + 40X + 100) = 4E(X^2) + 40E(X) + 100 = 424 + 40\sqrt{23}

so that

V(Y) = V(2X+10) = (424 + 40\sqrt{23}) - (2\sqrt{23} + 10)^2 = \boxed{232}

Alternatively, we can use the identity

V(aX+b) = a^2 V(X) \implies V(2X+10) = 4V(X) = 232

5 0
2 years ago
Trevor is analyzing a circle, y2 + x2 = 49, and a linear function g(x). Will they intersect?
melomori [17]
We have a circumference that is given by the following equation:

x^{2}+y^{2}=49

We can write this equation in its standard form as follows:

 x^{2}+y^{2}=7^{2} \\ where \ the \ radius \ r=7

On the other hand, the linear function is given as the following table:

x \ \ \ \ \ \ \ \ g(x) \\ -1 \ \ -9.2 \\ 0 \ \ \ \ \ -9 \\ 1 \ \ \ \ \ -8.8

To check if the circle and the line intersects, let's substitute the equation of the line into the equation of the circle to see if there is a real solution, so:

x^{2}+(0.2x-9)^{2}=49 \\ \\ \therefore x^{2}+0.04x^{2}-3.6x+81=49 \\ \\ \therefore 1.04x^{2}-36x+32=0 \\ \\ Solving \ for \ x: \\ x_{1}=33.70 \\ x_{2}=0.91 \\ \\ Solving \ for \ y: \\ y_{1}=0.2(33.70)-9=-2.26 \\ y_{2}=0.2(0.91)-9=-8.18

 Finally the intersects are:

 P_{1}(33.70, -2.26) \ and \ P_{2}(0.91, -8.18)
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7 0
2 years ago
Read 2 more answers
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