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Shkiper50 [21]
2 years ago
6

Some number is tripled and then cut in half.The result is increased by 5, and is equal to 20

Mathematics
1 answer:
Bad White [126]2 years ago
8 0
10 tripled equals 30 than 40 cut in half is 15 15+5=20 20=20
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I need help with this please help me ​
Tatiana [17]

Answer:last one

Step-by-step explanation:

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2 years ago
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Worth 50 points and I will mark brainliest.
olchik [2.2K]

x= -13 , y=11

Step-by-step explanation:

Using elimination method, make the x variable equal to eliminate the variable

-3x - y = -28

2x+ 3y=7

2(-3x-y =28)

3(2x+3y=7)

-6x - 2y =56

6x +9y=21

Apply addition

7y = 77

y=77/7 = 11

Use the value of y=11 in  

2x+ 3y=7

2x +3(11) =7

2x +33 =7

2x=7-33

2x= -26

x= -26/2 = -13

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7 0
3 years ago
Given the equation kx – 17 = 51 + x, where k=1, solve for X.
IgorC [24]

Answer:

  • No solution for x, when k = 1
  • x = 68/(k - 1), when k≠ 1

Step-by-step explanation:

<u>Given the equation</u>

  • kx – 17 = 51 + x, where k = 1,

<u>Solve for x:</u>

  • 1*x - 17 = 51 + x
  • x - 17 = x + 51
  • x - x = 51 + 17
  • 0 = 68,

Incorrect equation, no solution for x when k=1

<u>Solving for x when  k ≠ 1</u>

  • kx - 17 = 51 + x
  • kx - x = 51 + 17
  • x(k - 1) = 68
  • x = 68/(k - 1)
4 0
2 years ago
Describe a multiplication problem in which the product is between 0.005 and 1
Neporo4naja [7]
1 times 0.5
Is this what you mean?
Hopefully it is
7 0
3 years ago
Nbc news reported on may 2, 2013, that 1 in 20 children in the united states have a food allergy of some sort. consider selectin
Allushta [10]
Part 1:

The probability of a binary distribution x ~ bin(n, p) is given by

P(X=x)=(^n_x)p^x(1-p)^{n-x}

P(x\leq3)=P(0)+P(1)+P(2)+P(3) \\  \\ =(^{25}_0)(0.05)^0(1-0.05)^{25-0}+(^{25}_1)(0.05)^1(1-0.05)^{25-1} \\ +(^{25}_2)(0.05)^2(1-0.05)^{25-2}+(^{25}_3)(0.05)^3(1-0.05)^{25-3} \\  \\ =1\cdot1\cdot(0.95)^{25}+25\cdot(0.05)\cdot(0.95)^{24}+300\cdot(0.0025)\cdot(0.95)^{23} \\ +2300\cdot(0.000125)\cdot(0.95)^{22} \\  \\ =0.2774+0.3650+0.2305+0.0930 \\  \\ =\bold{0.9659}



Part 2:

P(X\ \textless \ 3)=P(0)+P(1)+P(2) \\  \\ =P(X\leq3)-P(X=3)=0.9659-0.0930 \\  \\ =\bold{0.8729}



Part 3:

P(X\geq4)=P(4)+P(5)+ . . . +P(25) \\  \\ =1-P(x\ \textless \ 4)=1-[P(0)+P(1)+P(2)+P(3)] \\  \\ =1-0.9659=\bold{0.0341}
8 0
3 years ago
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