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avanturin [10]
3 years ago
14

Find the area of the circle to the nearest tenth. use 3.14 for pie

Mathematics
2 answers:
vitfil [10]3 years ago
8 0
Hello,

<span>Find the area of the circle to the nearest tenth. use 3.14 for pie 
(4.4 is the other part)

</span>B 15.2
VikaD [51]3 years ago
3 0
I assume that 4.4 is the diameter,please do correct me if i am wrong.

To get the area of the circle,the formula is 丌r^2

to find the radius,we need ro devide the diameter by 2

thus the equations is
3.14  \times  ({4.4 \div 2})^{2}  \\  = 3.14 \times {2.2}^{2}  \\  = 15.196 \\  = 15.2(correct \: to \: the \: nearest \: tenth)
Therefore the answer is B.15.2

hope it helps!
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Answer:

The vertices of the image will have the coordinates

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B(-4, 3) → B'(2x-2, 2y-2) → B'(-10, 4)

C(1, 2) → C'(2x-2, 2y-2) → C'(0, 2)

D(-3, 0) → D'(2x-2, 2y-2) → D'(-8, -2)

Step-by-step explanation:

<em>Note: You missed to mention the vertices of a quadrilateral ABCD. So, I am assuming the following vertices. It would anyways clear your concept.</em>

<em />

Let us suppose

  • A(-5, 1)
  • B(-4, 3)
  • C(1, 2)
  • D(-3, 0)

We know that the rule of the dilation with the center of dilation at (2,2) by a scale factor of 2 is:

  • (x, y) → (2x-2, 2y-2)

Therefore, the vertices of the image will have the coordinates

A(-5, 1) → A'(2x-2, 2y-2) → A'(-12, 0)

B(-4, 3) → B'(2x-2, 2y-2) → B'(-10, 4)

C(1, 2) → C'(2x-2, 2y-2) → C'(0, 2)

D(-3, 0) → D'(2x-2, 2y-2) → D'(-8, -2)

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Step-by-step explanation:


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Answer:

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Step-by-step explanation:

9.78 \times 10^5 - 732,000\\= 9.78 \times 10^5 - 7.32 000\times 10^5\\= 9.78 \times 10^5 - 7.32\times 10^5\\= 2.46\times 10^5

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