Step-by-step explanation:
Given that,
a)
X ~ Bernoulli
and Y ~ Bernoulli 
X + Y = Z
The possible value for Z are Z = 0 when X = 0 and Y = 0
and Z = 1 when X = 0 and Y = 1 or when X = 1 and Y = 0
If X and Y can not be both equal to 1 , then the probability mass function of the random variable Z takes on the value of 0 for any value of Z other than 0 and 1,
Therefore Z is a Bernoulli random variable
b)
If X and Y can not be both equal to 1
then,
or 
and 

c)
If both X = 1 and Y = 1 then Z = 2
The possible values of the random variable Z are 0, 1 and 2.
since a Bernoulli variable should be take on only values 0 and 1 the random variable Z does not have Bernoulli distribution
The segment connecting a point on the preimage is equal to the segment connecting the point with its corresponding point on the image. Hence the relationship between the line of reflection is B. perpendicular bisector. It is not necessarily perpendicular as there are axis of symmetry that are not linear or 180 degrees
Answer:
what set of numbers??
you haven't provided any set of numbers
Set



so that the volume element is

The integral is then


and so evaluates to 0.