8y-3=15+2y what is x

What is the answer to 1/2 divided by 8/7

Alexandra [31]

7/16

Steps:

$\frac{1}{2} /\frac{8}{7} =\frac{1}{2} *\frac{7}{8} =\frac{7}{16}$

5 0

2 years ago

Will positive numbers always have a higher absolute value than negative numbers?

Reika [66]

-I5I=-5 vs. I-5I= 5

The absolute value will stay the same for both negative and positive. The result will change depending on where you put your absolute value signs.

6 0

3 years ago

Please hurry! How is the area of a rectangle related to the area of a triangle?

cricket20 [7]

The area of a rectangle is Base x height whereas the area of a triangle is Base x height divided by 2

5 0

3 years ago

Ray Cupple bought a basic car costing $26,500.00, with options costing $725.00. There is a 6% sales tax in his state and a combi

Alenkinab [10]

Given:
cost: 26,500
option: 725
total 27,225
tax (27,225 * 6%) 1,633.50
total 28,858.50
license & reg. fee 50.00
total cost 28,908.50 Choice D.

5 0

2 years ago

Read 2 more answers

A multiple-choice examination has 20 questions, each with five possible answers, only one of which is correct. Suppose that one

kari74 [83]

Answer:

The probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

Step-by-step explanation:

Let the random variable X represent the number of correctly answered questions.

It is provided all the questions have five options with only one correct option.

Then the probability of selecting the correct option is,

$P(X)=p=\frac{1}{5}=0.20$

There are n = 20 question in the exam.

It is also provided that a student taking the examination answers each of the questions with an independent random guess.

Then the random variable can be modeled by the Binomial distribution with parameters n = 20 and p = 0.20.

The probability mass function of X is:

$P(X=x)={20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x};\ x =0,1,2,3...$

Compute the probability that the student answers at least seventeen questions correctly as follows:

$P(X\geq 17)=P (X=17)+P (X=18)+P (X=19)+P (X=20)$

$=\sum\limits^{20}_{x=17}{{20\choose x}\ 0.20^{x}\ (1-0.20)^{20-x}}\\\\=0.00000000077+0.000000000032+0.00000000000084+0.000000000000042\\\\=0.000000000802882\\\\=8.03\times10^{-10}$

Thus, the probability that the student answers at least seventeen questions correctly is $8.03\times 10^{-10}$ .

4 0

3 years ago