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3 years ago

Give three numbers whose product is 9000

2 answers:

8 0

The first thing you should know is that there are many combinations of numbers in which the product can be equal to 9000.

For example, one of the possible combinations is given by:

$(30) * (15) * (20) = 9000$

Therefore, three numbers whose product is equal to 9000 are:

15, 20, 30.

Answer:

Three possible numbers whose product is equal to 9000 are given by:

15, 20, 30.

Klio2033 [76]3 years ago

3 0

Product means, the answer of numbers being multiplied with each other.
In the given situation, we need to find three numbers that will be multiplied with each other to get a product which is 9000. Now, let’s find the possible numbers to be multiplied:
=> 300 X 30 X 1
=> 9000 x 1
=> 9000

Or this one also applies:
=> 4500 x 2 x 1
=> 9000 x 1
=> 9000 There are a lot of ways to get a product of 9000 by multiplying 3 digits.

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After 24 pencil had sharpened, the pencil sharpener receptacle is full. If receptacle is emptied in average of twice a day, how

stiks02 [169]

Answer:

12 Pencils Sharpened

Step-by-step explanation:

Since the sharpener receptacle is emptied out 2 times every day.

Do 24*2 to get 48 pencils sharpened each day.

Now do 48/20 to get how many pencils a single person sharpens each day. Resulting in 2.4 pencils each day for 1 person.

Multiple 2.4 by 5 (Amount of days) to get 12 pencils in 5 days.

4 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20-%207%20%2B%20%20%5Cfrac%7Bf%7D%7B2%7D%20%3D%20%20-%201" id="TexFormula1" title=" - 7 + \f

vovikov84 [41]

First you had to add by seven from both sides of equation form.

$-7+\frac{f}{2}+7=-1+7$

Then simplify by equation.

$\frac{f}{2}=6$

Next, you multiply by two from both sides of equation form.

$\frac{2f}{2}=6*2$

And finally, simplify by equation.

$6*2=12$

$2*6=12$

$12/6=2$

$12/2=6$

$f=12$

Final answer: $\boxed{f=12}$

Hope this helps!

And thank you for posting your question at here on brainly, and have a great day.

-Charlie

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3 years ago

(3cosx-4sinx) + (3sinx+4cosx) = 5

Ksenya-84 [330]

(3 cos x-4 sin x)+(3sin x+4 cos x)=5
(3cos x+4cos x)+(-4sin x+3 sin x)=5
7 cos x-sin x=5
7cos x=5+sin x
(7 cos x)²=(5+sinx)²
49 cos²x=25+10 sinx+sin²x
49(1-sin²x)=25+10 sinx+sin²x
49-49sin²x=25+10sinx+sin²x
50 sin² x+10sinx-24=0

Sin x=[-10⁺₋√(100+4800)]/100=(-10⁺₋70)/100
We have two possible solutions:
sinx =(-10-70)/100=-0.8
x=sin⁻¹ (-0.8)=-53.13º (360º-53.13º=306.87)

sinx=(-10+70)/100=0.6
x=sin⁻¹ 0.6=36.87º

The solutions when 0≤x≤360º are: 36.87º and 306.87º.

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