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Lilit [14]
3 years ago
10

A 4 ft by 8ft rectangle has a perimeter of _ft and an area of _ ft/2

Mathematics
1 answer:
Setler [38]3 years ago
3 0
Perimeter = (4*2) + (8*2) = 8 + 16 = 24 ft
Area = 4 * 8 = 32 ft^2
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The distance between two cities on a map is 3 1/2 inches. The actual distance between the two cities is 28 miles.
lisabon 2012 [21]
Part A= 3.5 inches is equal to 8 miles

Part B= if 1 inch is 1 miles then on this map the cities are 28 inches apart.

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4 0
3 years ago
Multiplication made for 840 here's the numbers 11 3 4 5 2 3 7 6 14 what do I use to get 840 using only those numbers Help quick!
xxTIMURxx [149]

you can use the numbers 3, 4, 5, 2, 6, 7, and 14. You can multiply 3 times 280 to get 840, 210 times 4 to get 840, 5 times  168 to get 840, 2 times 420 to get 840, 140 times 6 to get 840, 7 times 120 to get 840, and 14 times 60 to get 840.

7 0
3 years ago
Suppose f(x) = x. Find the graph of f(x+2).
Ostrovityanka [42]
<h2>Hello!</h2>

The answer is:

The fourth graph.

<h2>Why?</h2>

We are given the following equation:

f(x)=x

Then, we need to find the graph of f(x+2) that will be equal to:

f(x+2)=x+2

y=x+2

Now, finding the x-axis interception, making "y" equal to 0, we have:

0=x+2

-2=x

Therefore, the x-axis interception point is located at (-2,0), it matches with the fourth graph.

Now, finding the y-axis interception, making "x" equal to 0, we have:

y=x+2

y=0+2=2

Therefore, the y-axis interception point is located at (0,2), it matches with the fourth graph.

Hence, we have that the graph of f(x+2) is the fourth graph since the second graph function cuts the x-axis at -2 and the y-axis at 2.

Have a nice day!

7 0
3 years ago
A soccer field is a rectangle 48 meters wide and 55 meters long. The coach asks players to run from one corner to the corner dia
Sindrei [870]

Answer:

Distance = 73 m

Step-by-step explanation:

Given that,

The length of a rectangle = 48 m

The width of a rectangle = 55 m

We need to find the diagonal distance. We can use the Pythagoras theorem to find it.

d^2=48^2+55^2\\\\d=\sqrt{5329}\\\\d=73\ m

So, the required distance is equal to 73 m.

5 0
3 years ago
If f(x) = 2x -­ 4 and g(x) = x^2+3, find each value.<br><br> 19. (f -­ g)(x)<br> 20. (f • g)(x)
just olya [345]

Step-by-step explanation:

(f - g)(x) = f(x) - g(x) \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = (2x - 4) - ( {x}^{2}  + 3) \\   \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: = 2x - 4 -  {x}^{2}  - 3 \\     \red{ \boxed{\therefore (f - g)(x)  =  -  {x}^{2}  + 2x - 7}}

5 0
3 years ago
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