Answer:
4$ for large 3$ for a small
Step-by-step explanation:
Answer:
13 =w
Step-by-step explanation:
-33 = 6 - 3w
Subtract 6 from each side
-33-6 = 6 - 3w-6
-39 = -3w
Divide each side by -3
-39/-3 = -3w/-3
13 =w
Answer:
Wednesday (9 weeks later) = 10th October.
Step-by-step explanation:
We label the days with the initials of the names.
M= 4
D = 7
B = 6
LCM of 6 +7 = 42
LCM of 6+7 + 4 = 84
We find 84 is the amount of days we need to add on to july 18th
We first find the weeks 84/7 = 9 weeks.
As Wednesday July 18th is exclusive it would be 84 days after this event.
18+ 84 = 102 days.
31 days in july = 31
31 days in Aug = 31
30 days in Sept = 30
= 92
102-92 = 10
We now know date is Wednesday 10th October
We can check 84 days = 9 weeks
13 days in July makes 31st july
31 days in Aug makes 31st Aug
30 days in Sept makes 30th Sept
= 74 days + 10 days = 84
10th October is the checked date and we know it is also a Wednesday as Wednesday had stayed exclusive and prove that there are 7 days in the week to account x 9, to account for an exact 9 weeks later duration.
Answer:
20 nickels and 26 dimes
Step-by-step explanation:
- She has $3.60 in nickels and dimes
- a nickel is $0.05 and a dime is $0.10
- let n be the number of nickels and d be the number of dimes
- thus the first equation is 3.6 = 0.05n +0.1d
- If she has 46 coins then n + d = 46
- then n = 46 - d
- sub n = 46 - d into 3.6 = 0.05n +0.1d
- 3.6 = 0.05(46 - d) + 0.1d
- 3.6 = 2.3 -0.05d+0.1d
- 1.3 = 0.05d
- 26 = d
- sub d = 26 into n+d=46
- n+26=46
- n=20
- Check by subbing n=20 and d=26 into 0.05n +0.1d
- 0.05(20) +0.1(26)
- 1+2.6 = 3.6
