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3 years ago

In an axiomatic system, which category do points, lines, and planes belong to?

2 answers:

8 0

I think the correct answer is undefined terms. In an axiomatic system, points, lines, and planes belong to the category of undefined terms. These systems do not have definite shape and sizes. Lines and planes can extend infinitely. I hope this answer helps you/

galben [10]3 years ago

4 0

Point, line and plane are undefined termseverything else is defined based on them - there are no other undefined terms in euclid's geometry - only those 3 listed above are undefined terms

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What is the estimate of 90/7 divided by 1 3/4

attashe74 [19]

Answer:

7×17/49

Step-by-step explanation:

90/7 × 4/7

90×4 / 7×7

360/49

7 17/49

6 0

3 years ago

What are the coordinates of the image after a dilation with the center at the origin and a scale factor of 2?

Marina CMI [18]

(-2, 2) (8,2) (8, -2) (-2, -2)

3 0

3 years ago

Read 2 more answers

If a radioactive isotope has a half-life of 6 hours and 12 milligrams is initially present, how much will

Serhud [2]

Answer:0.75 milligrams will be present in 24 hours

Step-by-step explanation:

Step 1

The formula for radioactive decay can be written as

N(t)=No (1/2)^(t/t 1/2)

where

No= The amount of the radioactive substance at time=0=milligrams

t 1/2= the half-life= 6 hours

t=24 hours

N(t) = the amount at time t

Step 2--- Solving

N(t)=No (1/2)^(t/t 1/2)

=N(t)=12 x ( 1/2) ^ (24/6)

= 12 x (1/2) ^4

= 12 x 0.0625

= 0.75 milligrams

3 0

3 years ago

2. Solve the equation using the quadratic formula. -4x2 + 40x + 16 = 0 Page 1 of 2

kumpel [21]

The solution to given quadratic equation is x = -0.3851 or x = 10.3851

Solution:

Given equation is:

$-4x^2 + 40x + 16 = 0$

To find: solve by quadratic equation formula

$\text {For a quadratic equation } a x^{2}+b x+c=0, \text { where } a \neq 0\\\\x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Using the above formula,

$\text{ For} -4x^2 + 40x + 16 = 0 \text{ we have } a = -4 ; b = 40 ; c = 16$

Substituting the values of a = -4 ; b = 40 ; c = 16 in above quadratic formula we get,

$\begin{aligned}&x=\frac{-40 \pm \sqrt{40^{2}-4(-4)(16)}}{2 \times-4}\\\\&x=\frac{-40 \pm \sqrt{1600+256}}{-8}\\\\&x=\frac{-40 \pm 43.081}{-8}\\\\&x=\frac{-40+43.081}{-8} \text { or } x=\frac{-40-43.081}{-8}\\\\&x=-0.3851 \text { or } x=10.3851\end{aligned}$

Thus the solution to given quadratic equation is x = - 0.3851 or x = 10.3851

8 0

3 years ago

What is RS? Round to the nearest tenth. I’m really struggling with this one.

tatiyna

Answer:

The RS is 6.48 in 739, 1500, 65

Hope this helps!

5 0

3 years ago