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3 years ago

9

In an axiomatic system, which category do points, lines, and planes belong to?

2 answers:

LekaFEV [45]3 years ago

8 0

I think the correct answer is undefined terms. <span>In an axiomatic system, points, lines, and planes belong to the category of undefined terms. These systems do not have definite shape and sizes. Lines and planes can extend infinitely. I hope this answer helps you/</span>

galben [10]3 years ago

4 0

Point, line and plane are undefined termseverything else is defined based on them - there are no other undefined terms in euclid's geometry - only those 3 listed above are undefined terms

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Help please this is confusing and also show your work

liq [111]

Answer:

B

Step-by-step explanation:

Volume is length · width · height, so you can add another column with the volumes:

8

9

6

3

Then you see that 9 is the highest volume.

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2 years ago

What is the value of y in the product of powers below?

Marat540 [252]

Answer:

y =0

Step-by-step explanation:

From the equation;

8³ × 8⁻⁵×8^y = 8⁻²= 1/8²

From the laws of indices;

aⁿ×aⁿ = a^2n

Therefore;

8³ × 8⁻⁵×8^y = 8^(3+-5+y)

8^(-2+y) = 8^-2 ; but the bases are the same and thus the exponents are the same;

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8 0

2 years ago

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Help with both questions offering 10 points

Alexandra [31]

Answer:

$\:\mathrm{First\: problem:\:}-2,\\\:\mathrm{Second\: problem:\: }-3$

Step-by-step explanation:

The slope of a line passing through points $(x_1, y_1)$ and $(x_2, y_2)$ is:

$m=\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}$

Plugging in any two points in the table we have:

<u>First problem:</u>

<u /> $m=\frac{1-5}{2-0}=\frac{-4}{2}=\fbox{$-2$}$ <u />

<u>Second problem:</u>

<u /> $m=\frac{-1-5}{2-0}=\frac{-6}{2}=\fbox{$-3$}$ <u />

8 0

3 years ago

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Distance between (-3,1) (1,5)

Mamont248 [21]

Answer & Step-by-step explanation:

For this problem, we will use the distance formula.

$d=\sqrt{(x2-x1)^2+(y2-y1)^2}$

For our (x1, y1), we will use (-3, 1). For our (x2, y2), we will use (1, 5). Now let's plug in our numbers and solve the problem.

$d=\sqrt{(1-(-3))^2+(5-1)^2}$

$d=\sqrt{4^2+4^2}$

$d=\sqrt{16 + 16}$

$d=\sqrt{32}$

$d=5.657$

So, the distance between (-3,1) and (1,5) is 5.657 units.

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2 years ago

Which value is equivalent to 12 + 24 ÷ 3? A) 8 B) 12 C) 20 D) 36

Montano1993 [528]

Answer:

c.20

Step-by-step explanation:

first step:24÷3=8

final step: 12+8=20

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3 years ago

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