Answer:
none of the above
Step-by-step explanation:
You can try the points in the equations (none works in any equation), or you can plot the points and lines (see attached). <em>You will not find any of the offered answer choices goes through the given points</em>.
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You can start with the 2-point form of the equation of a line. For points (x1, y1) and (x2, y2) that equation is ...
y = (y2 -y1)/(x2 -x1)·(x -x1) +y1
Filling in the given points, we get ...
y = (3 -1)/(2 -4)·(x -4) +1
y = 2/(-2)(x -4) +1 . . . . . simplify a bit
y = -x +4 +1 . . . . . . . . . simplify more
y = -x +5 . . . . . . . . . . . slope-intercept form
Um use fled but bfthb 123 tgbs
for the triangle...
b=2h
a=(1\2).bh=648
(1/2).2h.h=648
h2=648
h-18|2 in
h=36|2 in
for the rectangle...
L=3+w
a=l+w=648
{3+w}w=648
w2+3w-648=0
Only positive W values make sense here..
w-24=0
w=24 in
So..
L=3+24
Answer:
Step-by-step explanation:
Let's calculate the volume of the tank per each meter in height.
The volume of a cylinder is πr²h, where h is the height.
A height of 1 meter in a tank with a radius of 5 meters would hold a volume of:
Vol = (3.14)*(5 meters)^2 *(1 meter)
Vol (m^3) = 78.54 m^3 per 1 meter height.
If the tank were filled at a rate of 3 m^3/min, it would rise at at a rate of:
(78.54 m^3/meter)/(3 m^3/min) = 0.0382 meters/minute [38.2 cm/min
