Answer:
90
Step-by-step explanation:
1. Start by making functions for the numbers
2. You can plug in these functions into a graph to figure out the x variable
- The intersection point of the two lines reveals the x and y
- The x would be your answer
3. To check if your x is right, plug it back into the two equations
- .89(90)+36=116.1
- 1.29(90)=116.1
Answer:
P(A) = 0.2
P(B) = 0.25
P(A&B) = 0.05
P(A|B) = 0.2
P(A|B) = P(A) = 0.2
Step-by-step explanation:
P(A) is the probability that the selected student plays soccer.
Then:

P(B) is the probability that the selected student plays basketball.
Then:

P(A and B) is the probability that the selected student plays soccer and basketball:

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.
Answer:
the answer for your question is 9 31/42
Consider the inequality 
First, add (-3) to both sides of inequality:

Then multiply by (-1), remembering that multiplication by negative number changes the sign of inequality:

Now divide by 3:

Answer: correct choice is A.