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Katyanochek1 [597]
3 years ago
11

Find the estimates of x^2-x-2=3

Mathematics
1 answer:
Julli [10]3 years ago
5 0

Answer:

x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

Step-by-step explanation:

Given

Quadratic equation is

x^2-x-2=3\\x^2-x-5=0

Roots of the quadratic equation ax^2+bx+c=0 are

x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\

So, for the given equation roots are

x=\frac{1\pm\sqrt{(-1)^2-4(1)(-5)}}{2\cdot 1}\\x=\frac{1\pm\sqrt{21}}{2}\\so, x=\frac{1+\sqrt{21}}{2}\approx 2.79\\or\ x=\frac{1-\sqrt{21}}{2}\approx -1.79

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Answer: D: 4.5

Step-by-step explanation:

So the Equation I used for this would be

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Divide to get X by itself

and your left with

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Hope it helped.

3 0
3 years ago
consider the point (x,y) lying on the graph of y=(x+3)^1/2. let L be the distance between the points (x,y) and (4,0). write l as
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L=\sqrt{ (x-4)^2 + y^2 }
and 
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L=\sqrt{ (x-4)^2 + y^2 }=\sqrt{ (y^2 - 3-4)^2 + y^2 }=\sqrt{ (y^2-7)^2 + y^2 }


6 0
3 years ago
Do the side lengths 4, 8, and 10 form a triangle? Select the correct answer and reasoning.
STALIN [3.7K]

A. it forms a triangle

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Step-by-step explanation:

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