Answer:
6^21 = B
Step-by-step explanation:
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Answer:
answer is 4
Step-by-step explanation:
12 / 3
The cost of children’s ticket is $ 5
<h3><u>Solution:</u></h3>
Let "c" be the cost of one children ticket
Let "a" be the cost of one adult ticket
Given that adult ticket to a museum costs 3$ more than a children’s ticket
<em>Cost of one adult ticket = 3 + cost of one children ticket</em>
a = 3 + c ------ eqn 1
<em><u>Given that 200 adult tickets and 100 children tickets are sold, the total revenue is $2100</u></em>
200 adult tickets x cost of one adult ticket + 100 children tickets x cost of one children ticket = 2100

200a + 100c = 2100 ------ eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "c"</u></em>
Substitute eqn 1 in eqn 2
200(3 + c) + 100c = 2100
600 + 200c + 100c = 2100
600 + 300c = 2100
300c = 1500
<h3>c = 5</h3>
Thus the cost of children’s ticket is $ 5
Answer:
First mechanic worked for 10 hours and second mechanic worked for 15 hours.
Step-by-step explanation:
Let first mechanic worked for X hours and second mechanic worked for Y hours .
Now, according to the question , they worked for a total of 25 hours .
Thus ,
X + Y = 25.
Y = 25 - X -(1)
Also, first mechanic is charging $ 95 per hour and second mechanic is charging $115 per hour .
Thus, total money charged by them will be 95X + 115Y .
Which is given to be $2675 in the question.
Thus 95X + 115Y = 2675. -(2)
Putting equation 1 in equation 2 we get ,
95X + 2875 - 115X = 2675
20X = 200
X = 10 hours.
Thus , Y = 25 - X = 15 hours.
Thus first mechanic worked for 10 hours and second mechanic worked for 15 hours.