The transformations that would prove that circles A and C are similar are:
- A. Reflect A over the line y=x
- C. Dilate A by 3/2
<h3>How to prove that circle A and circle C are similar?</h3>
The circles are given as:
Circle A and B
Assume the following parameters:
- The center of circle A is (2,3) with a radius of 2
- The center of circle B is (3,2) with a radius of 3
To start with;
The circle A must be reflected across the line y = x with the following transformation rule:
(x,y) -> (y,x)
So, we have:
(2,3) -> (3,2)
Next, the radius of A must be dilated by 3/2 as follows:
New Radius = 3/2 * 2 = 3
After the transformations, we have the following parameters:
- The center of circle A is (3,2) with a radius of 3
- The center of circle B is (3,2) with a radius of 3
Notice that both circles now have the same center and radius.
Hence, both circles are similar
Read more about similar circles at:
brainly.com/question/9177979
Answer:
4(3x2y4)3/(2x3y5)4
Final result :
27
—————
4x6y8
Step by step solution :
Step 1 :
Equation at the end of step 1 :
(((3•(x2))•(y4))3)
4•——————————————————
((2x3•(y5))4)
Step 2 :
Equation at the end of step 2 :
((3x2 • (y4))3)
4 • ———————————————
24x12y20
Step 3 :
33x6y12
Simplify ————————
24x12y20
Dividing exponential expressions :
3.1 x6 divided by x12 = x(6 - 12) = x(-6) = 1/x6
Dividing exponential expressions :
3.2 y12 divided by y20 = y(12 - 20) = y(-8) = 1/y8
Equation at the end of step 3 :
27
4 • ——————
16x6y8
Step 4 :
Final result :
27
—————
4x6y8
Answer:
8.6 in²
Step-by-step explanation:
The area of the entire circle is A = πr², or A = π(2 in)².
This corresponds to a central angle of 2π radians, or 6.28 radians.
The area of the sector described above is just a certain fraction of that:
4.3 rad
-------------- * Area of circle = 0.685(4 * 3.14) = 8.6 in²
6.28 rad
Answer:
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Step-by-step explanation:
