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larisa86 [58]
3 years ago
15

Identify the inequality for the given graph.

Mathematics
1 answer:
DENIUS [597]3 years ago
7 0

Answer:

We. can see there's a  black point at -3.7 and an arrow going to the left.

As the arrow goes to the left, it must be less than -3.7 or less than or equal to -3.7, now, we will need to see the colour of the point to know which it is.

As there is a black point, -3.7 is also contained in this range...

What does that mean? That means it will be less than or equal to -3.7

So we know the correct option is a) less than or equal to -3.7, what we could write as (-\infty,-3.7].

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agasfer [191]
X = 180 - 150 = 30°

z = 180 - 100 = 80°

y = 180 - 30 - 80 = 70°

Answer: x = 30, y = 70, z = 80


6 0
4 years ago
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Help please jggvnhujff
saveliy_v [14]

Answer:

Step-by-step explanation:

<u><em>8).</em></u>  \left \{ {{4x+3y=1} \atop {x+y=2}} \right.

<em>(2)</em> × [ - 3 ]

4x + 3y = 1 ........ <em>(3)</em>

- 3x - 3y = - 6 .... <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

x = - 5

- 5 + y = 2 ⇒ y = 7

<em>( - 5 , 7 )</em>

<u><em>9).</em></u> \left \{ {{-9x+3y=18} \atop {2x+y=-4}} \right.

<em>(1)</em> ÷ [- 3]

3x - y = - 6  ......... <em>(3)</em>

2x + y = - 4 ........ <em>(4)</em>

<em>(3)</em> + <em>(4)</em>

5x = - 10 ⇒ x = - 2

2(- 2) + y = - 4 ⇒ y = 0

<em>(- 2, 0)</em>

<u><em>10).</em></u> \left \{ {{x-2y=14} \atop {10x-6y=0}} \right.

<em>(2)</em> ÷ 10

x - 0.6y = 0 ⇒ x = 0.6y -----> <em>(1)</em>

0.6y - 2y = 14

- 1.4y = 14

y = - 10

x - 2(- 10) = 14 ⇒ x = - 6

<em>(- 6, - 10)</em>

Now is your turn, you can do it!!

3 0
3 years ago
FIND THE MISSING SIDE LENGTH MATH HELP!!
Tom [10]

Answer:

n = 12

Step-by-step explanation:

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n = 12

5 0
3 years ago
What’s the standard form of this graph?
Anon25 [30]

Answer:

y = - |  (1/4)x - 1  | + 3

Step-by-step explanation:

if you are asking for the equation of the graph,

y = - |  (1/4)x - 1  | + 3

3 0
3 years ago
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Anettt [7]

Answer:

\frac{1}{2} ( cos40° + isin40°)

Step-by-step explanation:

To divide

\frac{r_{1(cosx_{1}+isinx_{1})  } }{r_{2}(cosx_{2}+isinx_{2})   }

= \frac{r_{1} }{r_{2} } [ cos(x₁ - x₂) + isin(x₁ - x₂)

Given

\frac{2(cos90+isin90}{4(cos50+isin50)}

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8 0
3 years ago
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