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alisha [4.7K]
3 years ago
12

Simplify.

Mathematics
1 answer:
lubasha [3.4K]3 years ago
7 0
<span>(-1/2)(4)(-2)(7y)(-1)

Just start multiplying!

-1/2 * 4 = -2
-2 * -2 = 4
4 * 7y = 28y
28y * -1 = -28y

Since that's not an option I suspect you're missing an x.</span>
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Use the functions h(x) = 2x + 5 and t(x) = 7x − 6 to complete the function operations listed below.
Komok [63]
A. (m+n)(x)=
5x+4+6x-9=
11x-5

B. (mn)(x)=
(5x+4)(6x-9)=
30x^2+24x-45x-36=
30x^2-21x-36

C. basically sub n(x) for x in m(x)
m(n(x))=
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5 0
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A golfer's score after playing on Friday was +2. His score for Saturday's round was -5. At the end of his round on Sunday, he wa
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What is the X intercept of line parallel to X axis
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Hi

Step-by-step explanation:

7 0
3 years ago
The length of a room is 8 feet more than twice width. If it takes 124 feet of molding to go around the perimeter of the room, wh
Aleksandr-060686 [28]

Answer:

Here's how we do it.

Let's say...

Width=W

Length=L=2w+8

Perimeter=2w+2(2w+8)=2w+4w+16=6w+16

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w=18

Now we know our width is 18...

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In conclusion,...

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I hope this helps y'all out!

4 0
4 years ago
A quiz consists of six multiple choice questions. Each question has four choices. A student who forgot to study guesses randomly
jeka94

Answer:

0.9945 = 99.45% probability that the student answers at most four questions correctly

Step-by-step explanation:

For each question, there are only two possible outcomes. Either the student answers correctly, or he/she does not. The probability of the student answering a question correctly is independent of any other question. This means that the binomial probability distribution is used to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

A quiz consists of six multiple choice questions.

This means that n = 6

Each question has four choices. Student guesses randomly.

This means that p = \frac{1}{4}

What is the probability that the student answers at most four questions correctly?

This is:

P(X \leq 4) = 1 - P(X > 4)

In which

P(X > 4) = P(X = 5) + P(X = 6). So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 5) = C_{6,5}.(0.25)^{5}.(0.75)^{1} = 0.0053

P(X = 6) = C_{6,6}.(0.25)^{6}.(0.75)^{0} = 0.0002

P(X > 4) = P(X = 5) + P(X = 6) = 0.0053 + 0.0002 = 0.0055

P(X \leq 4) = 1 - P(X > 4) = 1 - 0.0055 = 0.9945

0.9945 = 99.45% probability that the student answers at most four questions correctly

6 0
3 years ago
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