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ad-work [718]
3 years ago
8

four seniors and six juniors are competing for four places on a quiz bowl team. what is the approximate probability that all fou

r seniors will be chosen at random ?
Mathematics
2 answers:
12345 [234]3 years ago
6 0
The answer is 4 out of 10
uranmaximum [27]3 years ago
3 0

Answer:

The probability is:

                      4/10

Step-by-step explanation:

We are given:

four seniors and six juniors.

Number of seniors=4

Total number of people=10 ( since 6+4=10)

We are asked to fill four places on a quiz bowl team.

We are asked to find the probability that all four seniors will be chosen at random.

The probability is calculated as:

Ratio of the number of seniors to the total number of people.

            Hence, the probability is:

                                4/10

                       

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Jim’s father is older than 40 but younger than 50.If you can divide his age by 2,4,5,8,or 10 ,there will be a remainder of 1. Ho
CaHeK987 [17]

Answer:

Step-by-step explanation:

all you have to do is divide each number by 4, 41, 42, 43, 44, 45, 46, 47, 48, 49 ,and 50 until you get a remainder of 1. what I mean is do 2 divided by all the number from 40 50 and do the same with 4,5,8 and 10 until you find one of them that has a remainder of 1. (is a lot of work sorry could't tell you the anwer)

8 0
3 years ago
If you spin the spinner below twice, what is P(vowel, then Q)? A. 1/10 B. 1/9 C. 2/9 D. 1/12 Answer correctly and I will give br
bagirrra123 [75]

Answer:

The probability of spinning a vowel, then Q, is 1/12

Step-by-step explanation:

Find the probability of each event occurring. There are three vowels out of 6 letters and 1 Q, so the chances of spinning a vowel is 3/6 or 1/2 and the chances of spinning a Q is 1/6. Multiply the probabilities of the two events occurring to find the probability of a compound event. 1/2*1/6 = 1/12. Hope this helps!

4 0
3 years ago
Read 2 more answers
A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a
Rashid [163]

Answer:

Length of original rectangle: 11 units.

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

\text{Perimeter of new rectangle}=20

Step-by-step explanation:

Let x represent width of the original rectangle.  

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be x+6.

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be x-2.

The length of new rectangle would be x+6-4=x+2.

The area of new rectangle would be (x+2)(x-2).

Now we will equate area of new rectangle with 21 and solve for x as:

(x+2)(x-2)=21

Applying difference of squares, we will get:

x^2-2^2=21

x^2-4=21

x^2-4+4=21+4

x^2=25

Since width cannot be negative, so we will take positive square root of both sides.

\sqrt{x^2}=\sqrt{25}

x=5

Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be x+6\Rightarrow x+5=11.

Therefore, the length of original rectangle is 11 units.

\text{Area of original rectangle}=5\times 11

\text{Area of original rectangle}=55    

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}

We know that perimeter of rectangle is two times the sum of length and width.

\text{Perimeter of new rectangle}=2((x+2)+(x-2))

\text{Perimeter of new rectangle}=2((5+2)+(5-2))

\text{Perimeter of new rectangle}=2(7+3)

\text{Perimeter of new rectangle}=2(10)

\text{Perimeter of new rectangle}=20

Therefore, the perimeter of the new rectangle is 20 units.

7 0
3 years ago
Evaluate and simplify the following complex fraction
Arisa [49]

Answer:

-0.01851851851

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Which of the following points is a solution of |x|=-5
Naily [24]
An absolute value of any number cannot result in a negative number.

There are no possible points where |x| can equal -5.
4 0
2 years ago
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