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3 years ago

8

four seniors and six juniors are competing for four places on a quiz bowl team. what is the approximate probability that all fou

r seniors will be chosen at random ?

2 answers:

12345 [234]3 years ago

6 0

The answer is 4 out of 10

uranmaximum [27]3 years ago

3 0

Answer:

The probability is:

4/10

Step-by-step explanation:

We are given:

four seniors and six juniors.

Number of seniors=4

Total number of people=10 ( since 6+4=10)

We are asked to fill four places on a quiz bowl team.

We are asked to find the probability that all four seniors will be chosen at random.

The probability is calculated as:

Ratio of the number of seniors to the total number of people.

Hence, the probability is:

4/10

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Step-by-step explanation:

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A rectangle has a length 6 more than it's width if the width is decreased by 2 and the length decreased by 4 the resulting has a

Rashid [163]

Answer:

Length of original rectangle: 11 units.

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Step-by-step explanation:

Let x represent width of the original rectangle.

We have been given that a rectangle has a length 6 more than it's width. S the length of the original rectangle would be $x+6$ .

We have been given that when the width is decreased by 2 and the length decreased by 4 the resulting has an area of 21 square units.

The width of new rectangle would be $x-2$ .

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The area of new rectangle would be $(x+2)(x-2)$ .

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$(x+2)(x-2)=21$

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Since width cannot be negative, so we will take positive square root of both sides.

$\sqrt{x^2}=\sqrt{25}$

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Therefore, the width of original rectangle is 5 units.

Length of the original rectangle would be $x+6\Rightarrow x+5=11$ .

Therefore, the length of original rectangle is 11 units.

$\text{Area of original rectangle}=5\times 11$

$\text{Area of original rectangle}=55$

Therefore, area of the original rectangle is 55 square units.

Now we will find ratio of the original rectangle area to the new rectangle area as:

$\frac{\text{Area of original rectangle}}{\text{Area of new rectangle}}=\frac{55}{21}$

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$\text{Perimeter of new rectangle}=2((x+2)+(x-2))$

$\text{Perimeter of new rectangle}=2((5+2)+(5-2))$

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