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2 years ago

A chef cooks 9 lbs of chicken for 36 people and 17 lbs of chicken for 68 people

Mathematics

1 answer:

Anastaziya [24]2 years ago

5 0

Answer:

$\frac{1}{4} lbs/person$

Step-by-step explanation:

Here is the complete question: Find the rate of change for the situation:

A chef cooks 9 lbs of chicken for 36 people and 17 lbs of chicken for 68 people.

Given: 1st situation, A chef cook 9 lbs chicken for 36 people.

2nd situation, chef cook 17 lbs chicken for 68 people.

∴ 1st situation, weight of chicken per person= $\frac{9\ lbs}{36\ person} = \frac{9}{36}$

Weight of chicken per person= $\frac{1}{4} lbs/ person$

2nd situation, weight of chicken per person= $\frac{17\ lbs}{68\ person} = \frac{17}{68}$

Weight of chicken per person= $\frac{1}{4} lbs/ person$

In both the situation chef cook same amount of chicken per person, which is $\frac{1}{4} lbs/ person$

∴ Rate of change is $\frac{1}{4} lbs/ person$

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dem82 [27]

Answer:

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Step-by-step explanation:

Please consider the complete question:

Determine if the scenario involves mutually exclusive or overlapping events. Then find the probability.

A cooler contains twelve bottles of sports drink: four lemon-lime flavored, four orange flavored, and four fruit-punch flavored. You randomly grab a bottle. It is a lemon-lime or an orange.

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Let us find probability of finding one orange drink.

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$P(\text{Orange})=\frac{1}{3}$

Since probability of choosing a lemon lime doesn't effect probability of choosing orange drink, therefore, both events are mutually exclusive.

We know that probability of two mutually exclusive events is equal to the sum of both probabilities.

$P(\text{Lemon-lime or orange})=P(\text{Lemon-lime})+P(\text{Orange})$

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$P(\text{Lemon-lime or orange})=\frac{1+1}{3}$

$P(\text{Lemon-lime or orange})=\frac{2}{3}$

Therefore, the probability of choosing a lemon lime or orange is $\frac{2}{3}$ .

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