Biological molecules such as proteins and DNA reveal differences between humans and chimps that would have taken around 7 million years to accumulate.
<h3>What is DNA?</h3>
All known animals and viruses have genetic information in the form of deoxyribonucleic acid, a polymer consisting of two polynucleotide chains that coil around one another to form a double helix. Ribonucleic acid is a type of nucleic acid, as is DNA.
The two DNA strands are known as polynucleotides because they are constructed from simpler monomeric units called nucleotides.
The four nucleobases that contain nitrogen—cytosine (C), guanine (G), adenine (A), or thymine (T)—along with deoxyribose and a phosphate group—make up each nucleotide. The sugar of one nucleotide and the phosphate of the following make covalent bonds, creating what is known as the phospho-diester linkage, which results in an alternating sugar-phosphate backbone.
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I would say non-athletes would have a higher respiration rate as the athletes bodies are conditioned for the exercise and use to it and are better able to keep it as compared to non athletes.
Answer:
a) 9%.
b) 16.8%.
Explanation:
a).
We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%
Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails
9% Ab & 9% aB
i.e 0.09 Ab & 0.09 aB
On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab
∴
The probability that their first child will be Ab/ab will be
Pr ( Ab/ab) = (0.09) x (1)
= 0.09
= 9%.
b).
If the father produces 18% of recombinant gametes which entails
9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;
100%-18% = 82% ( non-recombinant gametes)
i.e genotype AB/ab = 82%
AB =41%; ab = 41%
AB = 0.41 ; ab = 0.41
Now, the probability that their first two children will both be ab/ab:
Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:
(0.41)(1) ×(0.41)(1)
= 0.1681
= 16.8%.