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Sveta_85 [38]
3 years ago
10

Ranchers who have herds of sheep often have problems keeping predators away from their herd while the sheep graze on grass. Whic

h term describes the sheep in this scenario?
Select all that apply.
A. Prey
B. Consumer
C. Primary consumers
D. Secondary consumers
Biology
1 answer:
natta225 [31]3 years ago
5 0

The term that describes the sheep in this scenario is prey, consumer and primary consumer.

A. Prey

B. Consumer

C. Primary consumers

<u>Explanation:</u>

It is given here that the sheep graze on the grass. Thus sheep is a consumer. When we get into the details of trophic levels in the ecosystem we can understand that autotrophs are the producers of an ecosystem. The organisms that feed on autotrophs are primary consumers.

Here grass is the producer and sheep is the primary consumer since it feeds on the grass. It is also given here that the ranchers have to keep the sheep away from predators. This makes the sheep a prey too. The animals that feed on primary consumers are called secondary consumers.

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Would athletes or non athletes have a higher respiration rate after exercise?
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Read 2 more answers
Two linked genes, A and B, are separated by 18 cM. A man with genotype AB/ab marries a woman who is ab/ab. The man’s father was
kolbaska11 [484]

Answer:

a) 9%.  

b) 16.8%.

Explanation:

a).

We are provided with the information that Two linked genes, A and B, are separated by 18 cM (centiMorgan). i.e the recombinant frequency is 18%

Also , the man's genotype is AB/ab... This only result to one explanation, that The man will definitely produce 18% of recombinant gametes which entails

9% Ab & 9% aB

i.e 0.09 Ab & 0.09 aB

On the other-hand, The mother ab/ab have tendency to produce just one single type of gamete which is ab

∴

The probability that their first child will be Ab/ab will be

Pr ( Ab/ab) = (0.09) x (1)

= 0.09

= 9%.  

b).

If the father produces 18% of recombinant gametes which entails

9% Ab & 9% aB , this typically implies that the number of the non-recombinant gametes will be;

100%-18% = 82%  ( non-recombinant gametes)

i.e genotype AB/ab = 82%

AB =41%; ab = 41%

AB = 0.41 ; ab = 0.41

Now, the probability that their first two children will both be ab/ab:

Using Multiplication Rule to calculate the probability that their first two children (ab/ab); we have:

 (0.41)(1) ×(0.41)(1)

= 0.1681

= 16.8%.

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4 years ago
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