These are in y=mx+b form where m=slope
sometimes b=0
vertical intercept means the y-intercept and the horizonatl intercept is the x intercept so the x intercept is when y=0 and the y intercept is when x=0 so the first one is
y=5x-15
slope=5
y-intercept=-15
x-intercept=3
y=7-x
this can be written as
y=-1x+7
slope=-1
y-intercept=7
x-intercept=7
4x=2y=12
we must get it into slope intercept form
divide the whole thing by 2x=y=12
we can disregard the 12 and get
2x=y or y=2x+0
slope=2
y-intercept=0
x-intercept=0
Check number.
The check number (7 in the figure) appears on the check twice: once in the upper right corner, and once at the bottom in magnetic ink.
_____
When you order checks, the check numbers in your order are all different. If you use the reorder form supplied, it has information that allows the check printer to make sure new checks start with a sequential number after the last of the old checks.
At goal post x= 35
<span>the height will be y= –0.03x2 + 1.6x= 19.25 > 15 </span>
<span>is 4.25 feet above the goal post.</span>
Given that
(2+i)²/(3+i)
On multiplying both numerator and the denominator with (3-i) then
⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]
⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]
⇛ [(2+i)²(3-i)]/[(3²-i²)
⇛ [(2+i)²(3-i)]/(9-i²)
⇛ [(2+i)²(3-i)]/[9-(-1)]
Since ,i² = -1
⇛ [(2+i)²(3-i)]/(9+1)
⇛ [(2+i)²(3-i)]/10
⇛ [{2²+i²+2(2)(i)}(3-i)]/10
⇛ (4+i²+4i)(3-i)/10
⇛ (4-1+4i)(3-i)/10
⇛ (3+4i)(3-i)/10
⇛ (9-3i+12i-4i²)/10
⇛ (9+9i-4(-1))/10
Since, i² = -1
⇛(9+9i+4)/10
⇛(13+9i)/10
⇛ (13/10)+ i (9/10)
We know that
The conjugate of a+ib is a-ib
So,
The conjugate of (13/10)+ i (9/10) is
(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)
<u>Answer:-</u>The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)
<em>Additional</em><em> comment</em><em>:</em>
- The conjugate of a+ib is a-ib and
- i = -1
- (a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².