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jonny [76]
3 years ago
15

What is the answer to the question

Mathematics
2 answers:
algol133 years ago
5 0
The angles given are opposite each other and are known as "vertical angles." Vertical Angles are congruent meaning that they have the same measure. So, we can just set the two expressions equal to each other and solve for x, like this:
4x+50=150

Subtract 50:
4x=100

Divide by 4:
x =  \frac{100}{4} = 25

Thus, x = 25°.

Sergeu [11.5K]3 years ago
4 0
Hello!

As you can see, the angles are congruent. These kind of angles are called vertical angles.

Vertical angles are angles opposite of each other. They always measure the same.

One of the angles measure 150°. That means the other angle also measures 150°.

4x + 50 = 150

150 - 50 = 100

That means 4x is equal to 100°

Divide both sides by 4

\frac{4x}{4} =  \frac{100}{4}

\framebox{x = 25 \°}
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Answer:

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Step-by-step explanation:

123/3

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3 years ago
I need to find the slope, vertical intercept and horizontal intercept of these 3 linear functions:
Bumek [7]
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sometimes b=0

vertical intercept means the y-intercept and the horizonatl intercept is the x intercept so the x intercept is when y=0 and the y intercept is when x=0 so the first one is

y=5x-15
slope=5
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y=7-x
this can be written as
y=-1x+7
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4x=2y=12
we must get it into slope intercept form
divide the whole thing by 2x=y=12
 we can disregard the 12 and get
2x=y or y=2x+0
slope=2
y-intercept=0
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3 years ago
The upper-right number on a check that helps you keep track of checks written is called a
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Math help please! Will give 20 points!
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At goal post x= 35 
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8 0
3 years ago
The conjugate of (2+i)²/3+i, in the form of a+ib, is
goblinko [34]

Given that

(2+i)²/(3+i)

On multiplying both numerator and the denominator with (3-i) then

⇛ [(2+i)²/(3+i)]×[(3-i)/(3-i)]

⇛ [(2+i)²(3-i)]/[(3+i)(3-i)]

⇛ [(2+i)²(3-i)]/[(3²-i²)

⇛ [(2+i)²(3-i)]/(9-i²)

⇛ [(2+i)²(3-i)]/[9-(-1)]

Since ,i² = -1

⇛ [(2+i)²(3-i)]/(9+1)

⇛ [(2+i)²(3-i)]/10

⇛ [{2²+i²+2(2)(i)}(3-i)]/10

⇛ (4+i²+4i)(3-i)/10

⇛ (4-1+4i)(3-i)/10

⇛ (3+4i)(3-i)/10

⇛ (9-3i+12i-4i²)/10

⇛ (9+9i-4(-1))/10

Since, i² = -1

⇛(9+9i+4)/10

⇛(13+9i)/10

⇛ (13/10)+ i (9/10)

We know that

The conjugate of a+ib is a-ib

So,

The conjugate of (13/10)+ i (9/10) is

(13/10)-i(9/10) ⇛ (13/10)+i (-9/10)

<u>Answer:-</u>The conjugate of (13/10)+ i (9/10) is (13/10)+i (-9/10)

<em>Additional</em><em> comment</em><em>:</em>

  • The conjugate of a+ib is a-ib and
  • i = -1
  • (a+b)² = a²+2ab+b² • (a+b)(a-b)=a²-b² •(a-b)²=a²-2ab+b².
5 0
2 years ago
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