The upper-right number on a check that helps you keep track of checks written is called a
1 answer:
Check number.
The check number (7 in the figure) appears on the check twice: once in the upper right corner, and once at the bottom in magnetic ink.
_____
When you order checks, the check numbers in your order are all different. If you use the reorder form supplied, it has information that allows the check printer to make sure new checks start with a sequential number after the last of the old checks.
The check number (7 in the figure) appears on the check twice: once in the upper right corner, and once at the bottom in magnetic ink.
_____
When you order checks, the check numbers in your order are all different. If you use the reorder form supplied, it has information that allows the check printer to make sure new checks start with a sequential number after the last of the old checks.
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Given function is
now we need to find the value of k such that function f(x) continuous everywhere.
We know that any function f(x) is continuous at point x=a if left hand limit and right hand limits at the point x=a are equal.
So we just need to find both left and right hand limits then set equal to each other to find the value of k
To find the left hand limit (LHD) we plug x=-4 into 3x+k
so LHD= 3(-4)+k
To find the Right hand limit (RHD) we plug x=-4 into
so RHD=
Now set both equal
k=-0.47
<u>Hence final answer is -0.47.</u>
Answer:
f(x) = 0.43 * *
*(x + 10)
Step-by-step explanation:
We have a 6th degree polynomial f(x)
r = 3 is a root of f with multiplicity 2
r = 1 is a root of f with multiplicity 3
f(-5) = -29721.6
f(-10) = 0
Then: f(x) = a*((x -3)^2 ) * ((x - 1)^3)*(x + 10)
f(-5) = a * (-8)^2 * (-6)^3 * (5) = -29,721.6
a* (64) * (-216)* 5 = -29,721.6
-a*69,120 = -29,721.6
a = -29,721.6/-69,120
a = 0.43
so
f(x) = 0.43 * *
*(x + 10)