16a+1 is the answer to your question
Answer:
I think the answer is B. Let me know if im wrong.
Step-by-step explanation:
Answer:
![X= \left[\begin{array}{ccc}-4&1\\5&-1\\\end{array}\right] \left[\begin{array}{ccc}21\\20\\\end{array}\right] \\](https://tex.z-dn.net/?f=X%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%261%5C%5C5%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C20%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
Step-by-step explanation:
Given the simultaneous equation
x+y=21
5x+4y=20
To write in matrix form, it must be in the form AX= b
X = A⁻¹b
A⁻¹ is the inverse of matrix A
A is a 2by2 matrix
X is the variables
b is a column matrix
The expression will therefore be written as;
![A=\left[\begin{array}{ccc}1&1\\5&4\\\end{array}\right] \\\\|A| = 1(4)- 5(1)\\|A| = 4-5\\|A| = -1\\A^{-1} = -\left[\begin{array}{ccc}4&-1\\-5&1\\\end{array}\right] \\\\A^{-1} = \left[\begin{array}{ccc}-4&1\\5&-1\\\end{array}\right] \\](https://tex.z-dn.net/?f=A%3D%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D1%261%5C%5C5%264%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5C%7CA%7C%20%3D%201%284%29-%205%281%29%5C%5C%7CA%7C%20%3D%204-5%5C%5C%7CA%7C%20%3D%20-1%5C%5CA%5E%7B-1%7D%20%3D%20-%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D4%26-1%5C%5C-5%261%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5C%5C%5C%5CA%5E%7B-1%7D%20%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%261%5C%5C5%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
Hence the required product matrix that represent X is;
![X= \left[\begin{array}{ccc}-4&1\\5&-1\\\end{array}\right] \left[\begin{array}{ccc}21\\20\\\end{array}\right] \\](https://tex.z-dn.net/?f=X%3D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D-4%261%5C%5C5%26-1%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D21%5C%5C20%5C%5C%5Cend%7Barray%7D%5Cright%5D%20%5C%5C)
Answer:
The amount charged for a hamburger is $11
Step-by-step explanation:
The function relating the amount d charged with the number of hamburgers is;
d = 3h + 8
The amount charged for a hamburger can be calculated by substituting the value 1 for h
Thus, we have;
d = 3(1) + 8 = $11