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rjkz [21]
3 years ago
10

A woman has twice as many dimes as quarters in her purse. If the dimes were quarters and the quarters were dimes, she would have

$1.20 more than she now has. How many of each does she have now?
Mathematics
2 answers:
Fudgin [204]3 years ago
6 0

Answer:

8 Quarters and 16 Dimes

Digiron [165]3 years ago
4 0
If x = # of quarters, then, the # of dimes will be equal to 2x. The total value (z) would be equal to:

z = 0.25x + 0.10(2x)

Then, since you switch the quarters and the dimes, and you have a new total, the resulting equation will be:

1.2 + z  = 0.25(2x) + 0.10(x)

Plug in the values you know:

1.2 + (0.25x + 0.10(2x)) = 0.25(2x) + 0.10(x)

Solve for x:

1.2 + (0.25x + 0.20x) = 0.50x + 0.10x
1.2 + 0.45x = 0.60x
1.2 = 0.15x
x = 1.2/0.15 = 8

This means that there are 8 Quarters in her bag right now. So, the amount of dimes is just 2x which is 16. So your answer will be:

She has 8 Quarters and 16 Dimes in her bag right now. Or, $3.60.

If this doesn't make sense, then tell me. I have some resources where I got the answer from to put it into simplest terms. I have the website if you want.
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horsena [70]

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\text{Equation of line,}\\\\~~~~~~~y - y_1 = m (x-x_1)\\\\\\\implies y-2 = \dfrac{52}3(x+2)~~~~~~~~~~~;[\text{Point-Slope form.]} \\\\\\\implies y-2 = \dfrac{52}3x + \dfrac{104}3\\\\\\\implies y = \dfrac{52}{3}x + \dfrac{104} 3 +2\\\\\\\implies y = \dfrac{52}3 x +\dfrac{110}3 ~~~~~~~~~~~~~~~;[\text{Slope -Intercept form}]

6 0
2 years ago
The sum of 5 times a larger number and twice a smaller is 5. The difference of 4 times the larger and the smaller number is 4. F
Gemiola [76]

Answer:

1 and 0

Step-by-step explanation:

Let's call the smaller number x and the larger number y.

This means 5y+2x=5.

Also, 4y-x=4.

This is a system of equations. There are two main ways two solve this.

Method 1: Substitution

5y+2x=5

4y-x=4

Solve for one of the variables, then substitute it back into one of the equations to solve for the other variable.

I will take 4y-x=4 and solve for x.

4y=4+x

x=4y-4

Then substitute for x in the other equation and solve for y.

5y+2x=5

5y+2(4y-4)=5

5y+8y-8=5

13y=13

y=1

Now we can go back to our equation for x and substitute for y.

x=4y-4

x=4(1)-4=0

y, the larger number, is 1 and

x, the smaller number, is 0

Method 2: Elimination

5y+2x=5

4y-x=4

Change the equations so that the coefficient of one of the variables in an equation is opposite the one in the other equation. Then add the equations and solve for each variable.

If I multiply both sides of the second equation, 4y-x=4, by 2, the coefficient of x will become -2. In the first equation, the coefficient is 2, so they will become opposites.

4y-x=4

becomes

8y-2x=8

Now we have 5y+2x=5 and 8y-2x=8.

Add the sides of both equations to cancel the x values.

5y+2x+8y-2x=5+8

13y=13

y=1

like last time, we can substitute for y in any of the original equations to get x.

5y+2x=5

5(1)+2x=5

5+2x=5

2x=0

x=0

y, the larger number, is 1 and

x, the smaller number, is 0

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Gelneren [198K]

Answer:

x^2 - 6x = -13

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Step-by-step explanation:

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Examples of measure of spread are: Mean, Median and Mode.

A measure of spread helps in giving an idea of how well the mean, or mode, or median, whichever of the three measure of spreads we use, represents the data under consideration. If the spread of values in the data set is large, that means there a lot of variation between the values of the data set. It is always better to have a small spread.

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