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4 years ago

4x/50 = 2/x what is the value of x in this proportion

Mathematics

1 answer:

viktelen [127]4 years ago

5 0

U do the butterfly or X multiplication method.
4x * x = 4x
50 * 2 = 100
4x/100 = 25

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Aleks04 [339]

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Step-by-step explanation: is the answer

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3 years ago

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19. Find the value of X (In the picture) (giving points to best answer/brainlest)

Tema [17]

Answer:

x = 61 degrees

Step-by-step explanation:

The triangle on the right is isosceles and the base angles are congruent

the sum of the inner angles of a triangle is 180 degrees

2 * 74 + y = 180

148 + y = 180

y = 32 degrees

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so we have that

90 - 32 = 58 degrees

Also the left triangle is isosceles, so we have

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3 years ago

5x +14+13x-2 i need help on these type of problems please

OleMash [197]

Answer:

18x+12

Step-by-step explanation:

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4 years ago

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The equation giving a family of ellipsoids is u = (x^2)/(a^2) + (y^2)/(b^2) + (z^2)/(c^2) . Find the unit vector normal to each

Fynjy0 [20]

Answer:

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Step-by-step explanation:

Given equation of ellipsoids,

$u\ =\ \dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2}$

The vector normal to the given equation of ellipsoid will be given by

$\vec{n}\ =\textrm{gradient of u}$

$=\bigtriangledown u$

$=\ (\dfrac{\partial{}}{\partial{x}}\hat{i}+ \dfrac{\partial{}}{\partial{y}}\hat{j}+ \dfrac{\partial{}}{\partial{z}}\hat{k})(\dfrac{x^2}{a^2}+\dfrac{y^2}{b^2}+\dfrac{z^2}{c^2})$

$=\ \dfrac{\partial{(\dfrac{x^2}{a^2})}}{\partial{x}}\hat{i}+\dfrac{\partial{(\dfrac{y^2}{b^2})}}{\partial{y}}\hat{j}+\dfrac{\partial{(\dfrac{z^2}{c^2})}}{\partial{z}}\hat{k}$

$=\ \dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}$

Hence, the unit normal vector can be given by,

$\hat{n}\ =\ \dfrac{\vec{n}}{\left|\vec{n}\right|}$

$=\ \dfrac{\dfrac{2x}{a^2}\hat{i}+\ \dfrac{2y}{b^2}\hat{j}+\ \dfrac{2z}{c^2}\hat{k}}{\sqrt{(\dfrac{2x}{a^2})^2+(\dfrac{2y}{b^2})^2+(\dfrac{2z}{c^2})^2}}$

$=\ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

Hence, the unit vector normal to each point of the given ellipsoid surface is

$\hat{n}\ =\ \ \dfrac{\dfrac{x}{a^2}\hat{i}+\ \dfrac{y}{b^2}\hat{j}+\ \dfrac{z}{c^2}\hat{k}}{\sqrt{(\dfrac{x}{a^2})^2+(\dfrac{y}{b^2})^2+(\dfrac{z}{c^2})^2}}$

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3 years ago

A game show awards 30 points for each correct answer and deducts 50 points for each in correct answer. A contestant answers 2 qu

mina [271]

Answer:

-10 points

Step-by-step explanation:

A game show awards 30 points for each correct answer and deducts 50 points for each in correct answer. A contestant answers 2 questions incorrectly and 3 questions correctly. What is his final score?

Let us say Initial number of points = 0

Hence,

He answers 2 incorrectly = 0 - 50 - 50

= -100

He answers 3 correctly =-100 + 30 + 30 + 30

His final score = -100 + 30 + 30 + 30

= -10 points

8 0

3 years ago